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lectrolysis: Given the oxidation and reduction equations involved in the KI electrolysis: Reduction reaction: 2 H2O(l) + 2e- → H2(g) + 2 OH-(aq) Oxidation reaction: 2 I-(aq) →I2 (g) + 2 e-  Calculate the average current that flowed through the electrolytic cell from the following information: Initial pH =7, Final pH = 12, Volume of KI solution = 30mL, Time of electrolysis is= 15min.

lectrolysis: Given the oxidation and reduction equations involved in the KI electrolysis: Reduction reaction: 2 H2O(l) + 2e- → H2(g) + 2 OH-(aq) Oxidation reaction: 2 I-(aq) →I2 (g) + 2 e-  Calculate the average current that flowed through the electrolytic cell from the following information: Initial pH =7, Final pH = 12, Volume of KI solution = 30mL, Time of electrolysis is= 15min.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Electrolysis:

Given the oxidation and reduction equations involved in the KI electrolysis:

Reduction reaction:

2 H2O(l) + 2e- → H2(g) + 2 OH-(aq)

Oxidation reaction:

2 I-(aq) →I2 (g) + 2 e- 

Calculate the average current that flowed through the electrolytic cell from the following information:

Initial pH =7, Final pH = 12, Volume of KI solution = 30mL,

Time of electrolysis is= 15min.

Electrolyti. Cell ( Non- Spontaneous) Calculato the Average Curnont in Amps. Amp= Coulomb/soc f= 96,500 Coulommbs/mob Data : ( P H=7 Final PH= 10.5 e Time = 1omin Vol KI solution 30.0ml Hzot +Of dathoda -GER A node:LEo Oven sll: 2I + 2H,0– I,+ Hz + OH" Calcu lations: -6 PoH - 3.5 [ONJ'= 3.16x10m JOH -6 9.5x1D mob e (96 500 Coul mol •92 caul. bosm o boo Soc 99 Coulemb boo see .0015 Coul./soc lomin .3 |.5 xID A mps
Transcribed Image Text:Electrolyti. Cell ( Non- Spontaneous) Calculato the Average Curnont in Amps. Amp= Coulomb/soc f= 96,500 Coulommbs/mob Data : ( P H=7 Final PH= 10.5 e Time = 1omin Vol KI solution 30.0ml Hzot +Of dathoda -GER A node:LEo Oven sll: 2I + 2H,0– I,+ Hz + OH" Calcu lations: -6 PoH - 3.5 [ONJ'= 3.16x10m JOH -6 9.5x1D mob e (96 500 Coul mol •92 caul. bosm o boo Soc 99 Coulemb boo see .0015 Coul./soc lomin .3 |.5 xID A mps
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