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Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Begin with Program 1 from Activity 4 of last week's LabAssignment1b. You are to convert that program to a new program that produces identical output. However, for all of the calculations, you are to instead create variables for all values that are either constants or are values that might vary in the calculation. Recall the following example from LabAssignment1b: # calculate/print area of rectangle of length 5 in. and height 3 in. print ("Area of rectangle is",5 * 3, "in^2") # area of rectangle in in^2 print () New code: New output: Area of rectangle is 15 in^2 Now, we know about variables and assignments statements, so let's modify the code as follows: # calculate/print area of rectangle of length 5 in. and height 3 in. length = 5 # inches height area = length * height # in^2 print ("Area of rectangle is", area, "in^2") print () Newer code: %3D = 3 # inches # area of rectangle in in^2 Newer output: Area of rectangle is 15 in^2
Transcribed Image Text:Begin with Program 1 from Activity 4 of last week's LabAssignment1b. You are to convert that program to a new program that produces identical output. However, for all of the calculations, you are to instead create variables for all values that are either constants or are values that might vary in the calculation. Recall the following example from LabAssignment1b: # calculate/print area of rectangle of length 5 in. and height 3 in. print ("Area of rectangle is",5 * 3, "in^2") # area of rectangle in in^2 print () New code: New output: Area of rectangle is 15 in^2 Now, we know about variables and assignments statements, so let's modify the code as follows: # calculate/print area of rectangle of length 5 in. and height 3 in. length = 5 # inches height area = length * height # in^2 print ("Area of rectangle is", area, "in^2") print () Newer code: %3D = 3 # inches # area of rectangle in in^2 Newer output: Area of rectangle is 15 in^2
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