Learning Goal: To use combustion analysis data to determine an empirical formula A molecular formula expresses the number of each kind of atom in a molecule. For example, the molecular formula for propene, C3H6, indicates three carbon atoms and six hydrogen atoms per molecule. This also means that one mole of propene contains three moles of carbon and six moles of hydrogen.An empirical formula expresses the mole ratio of the elements. The empirical formula for propene is CH2, indicating twice as much hydrogen as carbon. When analyzing unknown compounds in a lab, it is often possible to identify the mole ratios, and thus the empirical formula, but not the molecular formula.Notice that the molecular mass of propene, 3(12)+6(1)42 amu, is a multiple of the empirical formula mass, 1(12) + 2(1) = 14 amu An unknown compound contains only carbon, hydrogen, and oxygen (C, H,Oz). Combustion of 6.50 g of this compound produced 9.53 g of carbon dioxide and 3.90 g of water. Part A How many moles of carbon, C, were in the original sample? Express your answer to three significant figures and include the appropriate units.. ▸ View Available Hint(s) 0.217 mol Submit Previous Answers Correct Since there is one mole of carbon for every mole of carbon dioxide, the number of moles of each are equivalent. Part B How many moles of hydrogen, H, were in the original sample? Express your answer to three significant figures and include the appropriate units. ▸ View Available Hint(s) 0.216 ΜΑ ? mol Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Learning Goal:
To use combustion analysis data to determine an
empirical formula
A molecular formula expresses the number of each
kind of atom in a molecule. For example, the
molecular formula for propene, C3H6, indicates
three carbon atoms and six hydrogen atoms per
molecule. This also means that one mole of
propene contains three moles of carbon and six
moles of hydrogen.An empirical formula expresses
the mole ratio of the elements. The empirical
formula for propene is CH2, indicating twice as
much hydrogen as carbon. When analyzing
unknown compounds in a lab, it is often possible to
identify the mole ratios, and thus the empirical
formula, but not the molecular formula.Notice that
the molecular mass of propene,
3(12)+6(1)42 amu, is a multiple of the
empirical formula mass, 1(12) + 2(1) = 14 amu
An unknown compound contains only carbon, hydrogen, and oxygen (C, H,Oz). Combustion of 6.50 g of this compound
produced 9.53 g of carbon dioxide and 3.90 g of water.
Part A
How many moles of carbon, C, were in the original sample?
Express your answer to three significant figures and include the appropriate units..
▸ View Available Hint(s)
0.217 mol
Submit
Previous Answers
Correct
Since there is one mole of carbon for every mole of carbon dioxide, the number of moles of each are equivalent.
Part B
How many moles of hydrogen, H, were in the original sample?
Express your answer to three significant figures and include the appropriate units.
▸ View Available Hint(s)
0.216
ΜΑ
?
mol
Submit Previous Answers
X Incorrect; Try Again; 5 attempts remaining
Transcribed Image Text:Learning Goal: To use combustion analysis data to determine an empirical formula A molecular formula expresses the number of each kind of atom in a molecule. For example, the molecular formula for propene, C3H6, indicates three carbon atoms and six hydrogen atoms per molecule. This also means that one mole of propene contains three moles of carbon and six moles of hydrogen.An empirical formula expresses the mole ratio of the elements. The empirical formula for propene is CH2, indicating twice as much hydrogen as carbon. When analyzing unknown compounds in a lab, it is often possible to identify the mole ratios, and thus the empirical formula, but not the molecular formula.Notice that the molecular mass of propene, 3(12)+6(1)42 amu, is a multiple of the empirical formula mass, 1(12) + 2(1) = 14 amu An unknown compound contains only carbon, hydrogen, and oxygen (C, H,Oz). Combustion of 6.50 g of this compound produced 9.53 g of carbon dioxide and 3.90 g of water. Part A How many moles of carbon, C, were in the original sample? Express your answer to three significant figures and include the appropriate units.. ▸ View Available Hint(s) 0.217 mol Submit Previous Answers Correct Since there is one mole of carbon for every mole of carbon dioxide, the number of moles of each are equivalent. Part B How many moles of hydrogen, H, were in the original sample? Express your answer to three significant figures and include the appropriate units. ▸ View Available Hint(s) 0.216 ΜΑ ? mol Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining
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