Learning Goal: To understand the meaning of capacitance and ways of calculating capacitance Part E When a positive charge q is placed on a conductor that is insulated from ground, an electric field emanates from the conductor to ground, and the conductor will have a nonzero potential V relative to ground. If more charge is placed on the conductor, this voltage will increase proportionately. The ratio of charge to voltage is called the capacitance C of this conductor: C = q/V. Consider an air-filled charged capacitor. How can its capacitance be increased? O Increase the charge on the capacitor. O Decrease the charge on the capacitor. Figure < 1 of 1 O Increase the spacing between the plates of the capacitor. Decrease the spacing between the plates of the capacitor. Increase the length of the wires leading to the capacitor plates. A E Part F O O O O O
Learning Goal: To understand the meaning of capacitance and ways of calculating capacitance Part E When a positive charge q is placed on a conductor that is insulated from ground, an electric field emanates from the conductor to ground, and the conductor will have a nonzero potential V relative to ground. If more charge is placed on the conductor, this voltage will increase proportionately. The ratio of charge to voltage is called the capacitance C of this conductor: C = q/V. Consider an air-filled charged capacitor. How can its capacitance be increased? O Increase the charge on the capacitor. O Decrease the charge on the capacitor. Figure < 1 of 1 O Increase the spacing between the plates of the capacitor. Decrease the spacing between the plates of the capacitor. Increase the length of the wires leading to the capacitor plates. A E Part F O O O O O
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![Learning Goal:
To understand the meaning of capacitance and ways of
calculating capacitance
Part E
When a positive charge q is placed on a conductor that
is insulated from ground, an electric field emanates
from the conductor to ground, and the conductor will
have a nonzero potential V relative to ground. If more
charge is placed on the conductor, this voltage will
increase proportionately. The ratio of charge to voltage
is called the capacitance C of this conductor:
C = q/V.
Consider an air-filled charged capacitor. How can its capacitance be increased?
O Increase the charge on the capacitor.
Decrease the charge on the capacitor.
Figure
1 of 1
Increase the spacing between the plates of the capacitor.
O Decrease the spacing between the plates of the capacitor.
O Increase the length of the wires leading to the capacitor plates.
A
Part F](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c7b76d8-f494-4d12-967e-c0af4ccb19b8%2F3659ae37-d922-4f32-aa38-4cb3b90b4322%2F7uy1kd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Learning Goal:
To understand the meaning of capacitance and ways of
calculating capacitance
Part E
When a positive charge q is placed on a conductor that
is insulated from ground, an electric field emanates
from the conductor to ground, and the conductor will
have a nonzero potential V relative to ground. If more
charge is placed on the conductor, this voltage will
increase proportionately. The ratio of charge to voltage
is called the capacitance C of this conductor:
C = q/V.
Consider an air-filled charged capacitor. How can its capacitance be increased?
O Increase the charge on the capacitor.
Decrease the charge on the capacitor.
Figure
1 of 1
Increase the spacing between the plates of the capacitor.
O Decrease the spacing between the plates of the capacitor.
O Increase the length of the wires leading to the capacitor plates.
A
Part F
![Part F
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its
capacitance?
O Double the charge and double the plate area.
O Double the charge and double the plate separation.
Halve the charge and double the plate separation.
O Halve the charge and double the plate area.
O Halve the plate separation; double the plate area.
O Double the plate separation; halve the plate area.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c7b76d8-f494-4d12-967e-c0af4ccb19b8%2F3659ae37-d922-4f32-aa38-4cb3b90b4322%2F673odfc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part F
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its
capacitance?
O Double the charge and double the plate area.
O Double the charge and double the plate separation.
Halve the charge and double the plate separation.
O Halve the charge and double the plate area.
O Halve the plate separation; double the plate area.
O Double the plate separation; halve the plate area.
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