Learning Goal: To solve for forces in statcally indeterminate bars with axial loads The square bar shown (Figure 1) is 70 mm thick and 4.8 m long and is fixed supported at both ends. A load dire:ted leftward s appl ed et point C, as shown, L2 = 3.02 m from the left end. The madulus of elasticity is E = 100 GPa if point C moves 8 = 0 175 mm to the left, what is the applied force? When the number of reaction forces is greater than the number of equibrium equations, the system is statically indeteminete Solving for the reactions requires some additional equations. These additional equations come from considering compatib lity relationships (ie, continuity of displacements and relationships between dispiacements and loads). Express your answer with appropriate units to three significant figures. View Avallable Hint(s) For an axially loaded member, the compatibility relationship for the deflections can be written by seting the total relative axial displacement between the ends of the member to a known value The load- Value Units NL displacement re ationship 6- equation for the deflections Cnce the internal normet force of each segment is written in terms of the end reactions and applied loads, there is enough information to solve tor the reactions. Submit AE givas another Part B- Reaction with a known load Consider a new structure, whera the thickness of the bar is reduced to 35 mm from C to B (t is stil square) (Figure 2) and a- 3.02 m If the applied load is F - 390 kN, then what is the reaction at A? Let a positive reaction act to the right. The total tengh is still 4.8 m Figure 1 of 2 Express your answer with appropriate units to three significant figures. • View Available Hint(s) FA = l'alue Units Learning Goal: To solve for forces in statically indeterminate bars with Part B- Reaction with a known load axial loads When the number of react on forces is greater than the number of equilibrium equations, the system is statically indeterminate Solving for the react ons requires some additional equations. These additional equations come from considering compatibility relationships (1e., continuity of displacements and relaliuriships belweren displacemerils annd luads). Consider a new structure, where the thickness of the bar is reduced to 35 mm from C to B t is st i square) (F gure 2) and *- 3.02 m I the applied kad is F= 300 kN, then what is the reaction at A? Let a positive react on act to t1a rght. The total length is st l 4 8 m Express your answer with appropriate unita to three aignificant figures. > View Available Hint(s) For an axially loaded member, the compatibi ity relationship for the deflections can be written by setting the tota relative axial displacement between the ends of the member to a known value. The load- NL gives another AE Value Units displacement relationship a= equation for the deflections Once the internal nomel force of each segment is written in terms of the end reactions and applied loads, there is enough information to solve for the reactions. Submit Part C- Load point for equal forces Consider the structure from Fart B (Figure 2) What vake of a will led to equal reaction forces et A and B? Figure 2 of 2 Express your answer in meters to three significant figures. View Available Hint(s) vec 3v DA in

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Learning Goal:
To solve for forces in statically indeteminate bars with
axial loads
The square bar shown (Figure 1) is 70 mm thick and 4.8 m long and is fixed supported at both ends. Aload directed leftward s
appled at point C, as shown, La =3.02 m from the left end. The modulus of elasticity is E = 100 GPa if point C maves 8 =
0 175 mm to the left what is the applied force?
When the number of reaction forces is greater than
the number of equilitrium equations, the system is
Express your answer with appropriate units to three significant figures.
statically indeteminste Solving for the reactions
requires some additional equations. These additional
View Avallable Hint(s)
equations come from considering compatibility
relationships (1e, continuity of displacements and
relationships berween displacements ana ioads).
For an axially loaded member, the compatibility
relationship for the deflections can be written by
setting the total relative axial displacement between
the ends of the member to a known value The load-
F= Value
Units
NL
givas another
AE
displacement re ationship 6- E
Submit
equation for the deflections Cnce the internal normet
force of each segment is written in terms of the end
reactions and applied loads, there is enough
information to solve for the reactions.
Part B- Reaction with a known load
Consider a new structure, whera the thickness of the bar is reduced to 35 mm from C to B ot is stil square) (Figure 2) and
2- 3.02 m. if the applied load is F - 390 kN. then what is the reaction at A? Let a positive reaction act to the right. The total
lengh is still 4.8 m.
Figure
1 of 2
Express your answer with appropriate units to three significant figures.
View Available Hint(s)
B
FA=
Value
Units
Learning Goal:
To solve for forces in statically indeterminate bars with
axial loads
Part B - Reaction with a known load
When the number of react on forces is greater than
the number of equilibrium aquations, the system is
statically indeterminate Solving for the react ons
requires some additional equations These additional
equations come from considering compatibility
relationships (ie, continuity of displacements and
relsliuriships belweren displacments and luads).
Consider a new structure, where the thickness of the bar is reduced to 35 mm trom C to B t is st I square) (F gure 21 and
*- 3.02 m I the applied kad is F = 390 kN, then what is the eaction at A? Let a positiva react on act to tha rght. The totel
length is st ll 4 8 m
Express your anower with appropriate units to three significant figures.
• View Available Hint(s)
For an axially loaded member, the compatibi ity
relationship for the deflections can be written by
setting the tota relative axial displacement between
the ends of the member to a known value. The load-
?
NL
gives another
AE
Value
Units
displacement relationship a =E
equation for the deflections Once the internal nomal
force of each segment is written in terms of the end
reactions and spplied loads, there is enough
information to solive for the reactions.
Submit
Part C- Load point for equal forces
Consider the structure from Part B (Figure 23. What value of z will lesd to equal reaction forces et A and B?
Express your answer in meters to three significant figures.
> View Available Hint(s)
Figure
2 of 2
B
vec
F
Transcribed Image Text:Learning Goal: To solve for forces in statically indeteminate bars with axial loads The square bar shown (Figure 1) is 70 mm thick and 4.8 m long and is fixed supported at both ends. Aload directed leftward s appled at point C, as shown, La =3.02 m from the left end. The modulus of elasticity is E = 100 GPa if point C maves 8 = 0 175 mm to the left what is the applied force? When the number of reaction forces is greater than the number of equilitrium equations, the system is Express your answer with appropriate units to three significant figures. statically indeteminste Solving for the reactions requires some additional equations. These additional View Avallable Hint(s) equations come from considering compatibility relationships (1e, continuity of displacements and relationships berween displacements ana ioads). For an axially loaded member, the compatibility relationship for the deflections can be written by setting the total relative axial displacement between the ends of the member to a known value The load- F= Value Units NL givas another AE displacement re ationship 6- E Submit equation for the deflections Cnce the internal normet force of each segment is written in terms of the end reactions and applied loads, there is enough information to solve for the reactions. Part B- Reaction with a known load Consider a new structure, whera the thickness of the bar is reduced to 35 mm from C to B ot is stil square) (Figure 2) and 2- 3.02 m. if the applied load is F - 390 kN. then what is the reaction at A? Let a positive reaction act to the right. The total lengh is still 4.8 m. Figure 1 of 2 Express your answer with appropriate units to three significant figures. View Available Hint(s) B FA= Value Units Learning Goal: To solve for forces in statically indeterminate bars with axial loads Part B - Reaction with a known load When the number of react on forces is greater than the number of equilibrium aquations, the system is statically indeterminate Solving for the react ons requires some additional equations These additional equations come from considering compatibility relationships (ie, continuity of displacements and relsliuriships belweren displacments and luads). Consider a new structure, where the thickness of the bar is reduced to 35 mm trom C to B t is st I square) (F gure 21 and *- 3.02 m I the applied kad is F = 390 kN, then what is the eaction at A? Let a positiva react on act to tha rght. The totel length is st ll 4 8 m Express your anower with appropriate units to three significant figures. • View Available Hint(s) For an axially loaded member, the compatibi ity relationship for the deflections can be written by setting the tota relative axial displacement between the ends of the member to a known value. The load- ? NL gives another AE Value Units displacement relationship a =E equation for the deflections Once the internal nomal force of each segment is written in terms of the end reactions and spplied loads, there is enough information to solive for the reactions. Submit Part C- Load point for equal forces Consider the structure from Part B (Figure 23. What value of z will lesd to equal reaction forces et A and B? Express your answer in meters to three significant figures. > View Available Hint(s) Figure 2 of 2 B vec F
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