Learning Goal: To learn how to calculate the binding energy of a nucleus. The measured masses of nuclei are consistently lower than predicted by the sum of their particles. This discrepancy is called the mass defect, and it can be used to calculate the nuclear binding energy according to Einstein's famous equation AE-Ame² where AE is the energy produced. Am is the mass lost, and c= 3.00 x 10 m/s. Nuclear binding energy is the energy holding the nucleons together and is a measure of nuclear stability. The proton mass is 1.007276 amu, the neutron mass is 1.008665 amu. and the electron mass is 5.486x104 amu. Y Y Part A What is the expected mass of a fluorine-19 nucleus, based on the total mass of its protons and neutrons? Express your answer in atomic mass units using seven significant figures. ▸ View Available Hint(s) IVE ΑΣΦ Submit Part B. Am= S Submit The actual measured mass of a fluorine-10 atom is 18.998403 amu. What is the mass defect, Am, for a fluorine-19 nucleus? Express your answer in atomic mass units using six significant figures. View Available Hint(s) ΠΑΣΦ ? 3 amu ? amu Review | Constants | Periodic Tal

Learning Goal: To learn how to calculate the binding energy of a nucleus. The measured masses of nuclei are consistently lower than predicted by the sum of their particles. This discrepancy is called the mass defect, and it can be used to calculate the nuclear binding energy according to Einstein's famous equation AE-Ame² where AE is the energy produced. Am is the mass lost, and c= 3.00 x 10 m/s. Nuclear binding energy is the energy holding the nucleons together and is a measure of nuclear stability. The proton mass is 1.007276 amu, the neutron mass is 1.008665 amu. and the electron mass is 5.486x104 amu. Y Y Part A What is the expected mass of a fluorine-19 nucleus, based on the total mass of its protons and neutrons? Express your answer in atomic mass units using seven significant figures. ▸ View Available Hint(s) IVE ΑΣΦ Submit Part B. Am= S Submit The actual measured mass of a fluorine-10 atom is 18.998403 amu. What is the mass defect, Am, for a fluorine-19 nucleus? Express your answer in atomic mass units using six significant figures. View Available Hint(s) ΠΑΣΦ ? 3 amu ? amu Review | Constants | Periodic Tal

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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One potential uranium fission reaction is shown below.235U + n → 144Cs + 90Rb + 2 n[Atomic and nuclear masses are given in the reference table that is linked in Question - 0]Calculate the change in mass (Δm) in amu for a single atom of uranium undergoing fission by this reaction. Be sure to include the proper sign. Calculate the energy change (ΔE) in joules that occurs when a single atom of uranium undergoes fission by this process. Be sure to use the correct sign. Calculate the amount of energy released (in kJ) when 2.500 kg of uranium undergo fission by this process.
If the mass of one neutron is 1.00866 amu, the mass of one proton is 1.00728 amu, and the mass of a Sulfur-34 nucleus is 33.96786 amu, calculate the binding energy for the 345 nucleus. A) 1.44 x 1010 kJ/mol C) 4.57 × 109 kJ/mol B) 7.53 x 109 kJ/mol D) 2.74 x 1010 kJ/mol
Calculate the nuclear binding energy (in joules) and the nuclear binding energy per nucleon of: 151 Eu 63 (150.919860 amu) Use 1.008665 amu for the mass of a neutron, 1.007276 amu for the mass of a proton, and 1.007825 amu for the mass of an 1 H 1 atom. (Round each final answer to 4 significant figures.) Enter your answers in scientific notation. ______J_____ J/nucleon
A 1H atom has a mass of 1.673533 10–24 g, while a neutron has a mass of 1.674927 10–24 g. A titanium-48 atom has a mass of 7.9619431 10–23 g. What is titanium-48's nuclear binding energy (in J)? a. 3.44 × 10–10 J b. 1.12 × 10–10 J c. 6.70 × 10–11 J d. 7.72 × 10–11 J
The mass defect in the formation of an alpha particle from two protons and two neutrons is 0.0305 g/mol. The nuclear binding energy for this alpha particle in J/mol is___ Use: E = mc² where the speed of light is 3.00 x 108 m/s. Note of the following conversion: 1 kg = 1000 g 1 J = 1 kg m²/s²
Each of the following nuclei undergoes either beta decay or positron emission. Predict the type of emission for each: (a) tritium, 3 1H, (b) 89 38Sr, (c) iodine-120, (d) silver-102.
When an electron and its anti-particle, a positron, collide, they annihilate each other. Calculate the energy released in this process, in J. (The positron mass is the same as the electron mass, namely 9.11 ×1031 kg.)
I want to know how to solve this
12. Calculate the nuclear binding energy per one nucleon for the Be-8 isotope (eight nucleons). Here are some helpful data: {B.E = Am .c2 c=3.00 x 108 m/s and I J= kg.m2/s2} 1.32931 x 10-23 g 1.67262158 × 10–24 g 1.67492716 x 10–24 g Actual mass of Be- 8 proton mass neutron mass a) 1.2035 x 10–6 J/nucleon c) 1.092263 x 10–12 J/nucleon b) 1.092263 x 10–9 J/nucleon d) 8.7381 x 10–12 J/nucleon
A student is surprised by her work. She feels that the nuclear binding energy is high for oxygen-16. Her work is as follows: Part 1: One neutron's mass is 1.008665 amu, while one proton's mass is 1.007276 amu. In oxygen - 16 there are 8 protons and 8 neutrons with a total mass of 16.127528 amu. (1.007276x8)+(1.008665x8)=16.127528 Part 2: Because the mass of oxygen-16 is 15.994915 amu, the difference between the mass of an atom and the sum of its protons and neutrons is the mass defect. The mass defect for oxygen-16 is 0.132613 amu. 16.127528-15.994915 0.132613 Part 3: The missing mass in oxygen-16 is converted to the nuclear binding energy using Einstein's equation E = mc². The amount of energy is 1.19x1016 J, which I think is too high. E = mc² = (0.132613) × (3.00 x 108)2=1.193×1016 J Which part of the solution was there an error? a) Parts 2 and 3. b) Part 3 only. c) Parts 1 and 2. d) No error.
Q3 Radium-224 decays through the pathway a, a, a, ß, a, ß. What intermediates are formed in this decay series? What is the final stable nucleus formed?
I need help balancing these nuclear equations. Thank you