Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΕ = 0 ΣFy=0 Στο = 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. Submit Part B Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft. P₁ H P₂ a B C D a/2 a/2 Determine FCG and FGH, the magnitudes of the forces in members CG and GH, respectively, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answers numerically in pounds to three significant figures separated by a comma. ▸ View Available Hint(s) FCG, FGH = ΜΕ ΑΣΦ Η vec ? lb

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter10: Virtual Work And Potential Energy
Section: Chapter Questions
Problem 10.61P
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Please answer part B correctly
Learning Goal:
To apply the method of sections to find the forces in
specific members of a truss.
The method of sections is used to find the force in a
specific member of a truss and is based on the
principle that, if a body is in equilibrium, then every
part of that body is also in equilibrium. When
applied, the method of sections "cuts" or sections
the members of a truss and exposes their internal
forces. To find the unknown internal member
forces, the free-body diagram of a section is drawn
and the equations of equilibrium are applied:
ΣΕ = 0
ΣFy=0
Στο = 0
Because there are only three independent
equilibrium equations, section cuts should be made
such that there are not more than three members
that have unknown forces.
Submit
Part B
Previous Answers
Correct
Important: If you use this answer in later parts, use the full unrounded value in your calculations.
As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft.
P₁
H
P₂
a
B C D
a/2
a/2
Determine FCG and FGH, the magnitudes of the forces in
members CG and GH, respectively, using the method of sections. Assume for your calculations that each member is
in tension, and include in your response the sign of each force that you obtain by applying this assumption.
Express your answers numerically in pounds to three significant figures separated by a comma.
▸ View Available Hint(s)
FCG, FGH
=
ΜΕ ΑΣΦ Η
vec
?
lb
Transcribed Image Text:Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΕ = 0 ΣFy=0 Στο = 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. Submit Part B Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft. P₁ H P₂ a B C D a/2 a/2 Determine FCG and FGH, the magnitudes of the forces in members CG and GH, respectively, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answers numerically in pounds to three significant figures separated by a comma. ▸ View Available Hint(s) FCG, FGH = ΜΕ ΑΣΦ Η vec ? lb
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