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Learning Goal: Application of Newton's Laws This problem has similarity to Openstax textbook example 4.8, which was also solved in lecture. Pay attention to the details of geometry. Rescue It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) T₁, = T₁, = 7₂x = T₂, = W, = ZF, -T, +T+W, SF, -T₁, +T+W, Newton's 2nd law F=ma, EF=ma, A person whose mass is m = 54.0 kg in the picture is being rescued. from a burning building and she is being held motionless momentarily by the two tension forces, T1 and T2 in the two ropes. The angle of T₁ (in the left rope) to the vertical is 15°, and the angle of T2 (in the right rope) above the horizontal is 10°. The magnitude of the gravitational acceleration is 9.80 m/s². You will find the magnitudes of T₁ and T₂. Submit Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. Now the table on the right side of the figure is complete with T₁ and T₂ as space holders. You can write up F, and EF,, with T₁ and T₂ as space holders. The person is being held Motionless. Based on this fact, you can set up two equations involing T₁ and T₂ by applying Newton's Laws (1st or 2nd). Then you solve for T₁ and T₂ (both should be positive). ▾ Part D - The magnitude of T₁ is: magnitude T₁ = Submit 1971 ΑΣΦ Request Answer Part E - The magnitude of T2 is: ? N

Learning Goal: Application of Newton's Laws This problem has similarity to Openstax textbook example 4.8, which was also solved in lecture. Pay attention to the details of geometry. Rescue It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) T₁, = T₁, = 7₂x = T₂, = W, = ZF, -T, +T+W, SF, -T₁, +T+W, Newton's 2nd law F=ma, EF=ma, A person whose mass is m = 54.0 kg in the picture is being rescued. from a burning building and she is being held motionless momentarily by the two tension forces, T1 and T2 in the two ropes. The angle of T₁ (in the left rope) to the vertical is 15°, and the angle of T2 (in the right rope) above the horizontal is 10°. The magnitude of the gravitational acceleration is 9.80 m/s². You will find the magnitudes of T₁ and T₂. Submit Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. Now the table on the right side of the figure is complete with T₁ and T₂ as space holders. You can write up F, and EF,, with T₁ and T₂ as space holders. The person is being held Motionless. Based on this fact, you can set up two equations involing T₁ and T₂ by applying Newton's Laws (1st or 2nd). Then you solve for T₁ and T₂ (both should be positive). ▾ Part D - The magnitude of T₁ is: magnitude T₁ = Submit 1971 ΑΣΦ Request Answer Part E - The magnitude of T2 is: ? N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Learning Goal: Application of Newton's Laws This problem has similarity to Openstax textbook example 4.8, which was also solved in lecture. Pay attention to the details of geometry. 15° T₁ T₂ Rescue J.10° It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) T₁x = T₂ Newton's 2nd law = Wx= ΣF = T₁+T₂x +W₂ ΣF = max T₁₂ T2y = = W, = ΣF, = T₁, +T₂, +W, ΣΕ, = may A person whose mass is m = 54.0 kg in the picture is being rescued from a burning building and she is being held motionless momentarily by the two tension forces, T₁ and T2 in the two ropes. The angle of T₁ (in the left rope) to the vertical is 15⁰, and the angle of T2 (in the right rope) above the horizontal is 10⁰. The magnitude of the gravitational acceleration is 9.80 m/s². You will find the magnitudes of T₁ and T2. Submit Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. Now the table on the right side of the figure is complete with T₁ and T₂ as space holders. You can write up ΣF and ΣFy, with T₁ and T₂ as space holders. The person is being held Motionless. Based on this fact, you can set up two equations involing T₁ and T₂ by applying Newton's Laws (1st or 2nd). Then you solve for T₁ and T₂ (both should be positive). Part D- The magnitude of T₁ is: magnitude T₁ = Submit Request Answer Part E - The magnitude of T2 is: magnitude T2 = Submit ΑΣΦ Request Answer ΑΣΦ ? N N
Transcribed Image Text:Learning Goal: Application of Newton's Laws This problem has similarity to Openstax textbook example 4.8, which was also solved in lecture. Pay attention to the details of geometry. 15° T₁ T₂ Rescue J.10° It is extremely helpful to make a table like this, fill in each item (use "space holders" for unknown quantities) T₁x = T₂ Newton's 2nd law = Wx= ΣF = T₁+T₂x +W₂ ΣF = max T₁₂ T2y = = W, = ΣF, = T₁, +T₂, +W, ΣΕ, = may A person whose mass is m = 54.0 kg in the picture is being rescued from a burning building and she is being held motionless momentarily by the two tension forces, T₁ and T2 in the two ropes. The angle of T₁ (in the left rope) to the vertical is 15⁰, and the angle of T2 (in the right rope) above the horizontal is 10⁰. The magnitude of the gravitational acceleration is 9.80 m/s². You will find the magnitudes of T₁ and T2. Submit Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations. Now the table on the right side of the figure is complete with T₁ and T₂ as space holders. You can write up ΣF and ΣFy, with T₁ and T₂ as space holders. The person is being held Motionless. Based on this fact, you can set up two equations involing T₁ and T₂ by applying Newton's Laws (1st or 2nd). Then you solve for T₁ and T₂ (both should be positive). Part D- The magnitude of T₁ is: magnitude T₁ = Submit Request Answer Part E - The magnitude of T2 is: magnitude T2 = Submit ΑΣΦ Request Answer ΑΣΦ ? N N
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