I'm placed 35 kilograms of leaves onto a plastic tarp, and am dragging it across the lawn. The force I'm pulling with is 200N, directed 30 degrees above the horizontal. Friction coefficients between the tarp and the lawn are µs = 0.5 and µx = 0.3. a.) roughly to scale. Draw a free body diagram of the tarp-full-of-leaves, including all relevant forces drawn b.) What normal force is acting on the tarp full of leaves? Am I pulling hard enough to get the tarp moving? If not, how hard would I have to pull? If so, what acceleration will the leaf pile have? с.)
I'm placed 35 kilograms of leaves onto a plastic tarp, and am dragging it across the lawn. The force I'm pulling with is 200N, directed 30 degrees above the horizontal. Friction coefficients between the tarp and the lawn are µs = 0.5 and µx = 0.3. a.) roughly to scale. Draw a free body diagram of the tarp-full-of-leaves, including all relevant forces drawn b.) What normal force is acting on the tarp full of leaves? Am I pulling hard enough to get the tarp moving? If not, how hard would I have to pull? If so, what acceleration will the leaf pile have? с.)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please help me with these problems. We are using algebra based physics, not calc based
![**Problem Statement:**
I’m placing 35 kilograms of leaves onto a plastic tarp and am dragging it across the lawn. The force I’m pulling with is 200 N, directed 30 degrees above the horizontal. Friction coefficients between the tarp and the lawn are \(\mu_s = 0.5\) and \(\mu_k = 0.3\).
a.) Draw a free body diagram of the tarp-full-of-leaves, including all relevant forces drawn roughly to scale.
b.) What normal force is acting on the tarp full of leaves?
c.) Am I pulling hard enough to get the tarp moving?
If not, how hard would I have to pull? If so, what acceleration will the leaf pile have?
**Detailed Explanation:**
**a.) Free Body Diagram Explanation:**
To create a free body diagram for the tarp-full-of-leaves:
- Draw a reference line representing the horizontal ground.
- Indicate the gravitational force acting downwards, \( F_g = mg \), where \( m = 35 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \).
- Represent the pulling force of 200 N directed 30 degrees above the horizontal.
- Show the normal force acting perpendicular to the ground.
- Include the frictional force opposite to the direction of motion.
**b.) Normal Force Calculation:**
The normal force can be calculated using the balance of forces in the vertical direction. The weight and the vertical component of the pulling force need to be considered.
\[ F_g = mg = 35 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 343 \, \text{N} \]
The vertical component of the pulling force is:
\[ F_{py} = 200 \, \text{N} \times \sin(30^\circ) = 100 \, \text{N} \]
The normal force \( N \) is:
\[ N = F_g - F_{py} = 343 \, \text{N} - 100 \, \text{N} = 243 \, \text{N} \]
**c.) Determine Movement and Acceleration:**
Determine if the pulling force overcomes static friction:
The maximum static friction is:
\[ f_s = \mu_s \cdot N = 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1035f9e-9761-429f-91d8-dd3cf9141919%2Fe6d61dfb-9b67-4732-96b8-05a35a08aa5a%2Fgm57ww7_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
I’m placing 35 kilograms of leaves onto a plastic tarp and am dragging it across the lawn. The force I’m pulling with is 200 N, directed 30 degrees above the horizontal. Friction coefficients between the tarp and the lawn are \(\mu_s = 0.5\) and \(\mu_k = 0.3\).
a.) Draw a free body diagram of the tarp-full-of-leaves, including all relevant forces drawn roughly to scale.
b.) What normal force is acting on the tarp full of leaves?
c.) Am I pulling hard enough to get the tarp moving?
If not, how hard would I have to pull? If so, what acceleration will the leaf pile have?
**Detailed Explanation:**
**a.) Free Body Diagram Explanation:**
To create a free body diagram for the tarp-full-of-leaves:
- Draw a reference line representing the horizontal ground.
- Indicate the gravitational force acting downwards, \( F_g = mg \), where \( m = 35 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \).
- Represent the pulling force of 200 N directed 30 degrees above the horizontal.
- Show the normal force acting perpendicular to the ground.
- Include the frictional force opposite to the direction of motion.
**b.) Normal Force Calculation:**
The normal force can be calculated using the balance of forces in the vertical direction. The weight and the vertical component of the pulling force need to be considered.
\[ F_g = mg = 35 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 343 \, \text{N} \]
The vertical component of the pulling force is:
\[ F_{py} = 200 \, \text{N} \times \sin(30^\circ) = 100 \, \text{N} \]
The normal force \( N \) is:
\[ N = F_g - F_{py} = 343 \, \text{N} - 100 \, \text{N} = 243 \, \text{N} \]
**c.) Determine Movement and Acceleration:**
Determine if the pulling force overcomes static friction:
The maximum static friction is:
\[ f_s = \mu_s \cdot N = 0.
Transcribed Image Text:**Title: Understanding Height Changes While Inverted vs. Standing**
**Educational Content:**
**Objective:**
Estimate the change in height an average person experiences while hanging upside-down, by their feet, as opposed to while standing on level ground.
**Explanation:**
When a person hangs upside-down, gravitational forces act differently on the body compared to when standing upright. This can cause mild decompression of the spine and slight extension of the body, leading to a temporary increase in height. The change is usually very small and varies depending on individual factors such as body composition, flexibility, and spine health.
Understanding these differences can help in fields such as anatomy, physics, and even space travel, where gravitational forces are altered.
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