LEARN MORE REMARKS In part (a), note that cos (-) = cos 0; however, sin (-0) = -sin 0. The negative sign of A, reflects the fact that displacement in the y-direction is downward. QUESTION What other functions, if any, can be used to find the angle in part (b)? (Select all that apply.) = cos 0 cos -1 0 = sin-1 ) 0 = sin-1 (√ 2 B. +By = cos-1 B. Bx By 2 X +By B X Bx 2 + B + B ¹ (²) B none of those listed 2 2 X
LEARN MORE REMARKS In part (a), note that cos (-) = cos 0; however, sin (-0) = -sin 0. The negative sign of A, reflects the fact that displacement in the y-direction is downward. QUESTION What other functions, if any, can be used to find the angle in part (b)? (Select all that apply.) = cos 0 cos -1 0 = sin-1 ) 0 = sin-1 (√ 2 B. +By = cos-1 B. Bx By 2 X +By B X Bx 2 + B + B ¹ (²) B none of those listed 2 2 X
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![LEARN MORE
REMARKS In part (a), note that cos (-0) = cos 0; however, sin (-0) = -sin 0. The negative sign of Ay
reflects the fact that displacement in the y-direction is downward.
QUESTION What other functions, if any, can be used to find the angle in part (b)? (Select all that
apply.)
0 = cos
0 = COS
0 =
0 =
-1
-1
sin-1
0 = cos
sin-1
B
B
Bx
2
X
B
у
(√²+
2
B
-1
X
B
X
(√²+0)
2
B + B.
X
y
+ B
By
2
2
Bx + By
B + B
2
у
none of those listed
2
y
2
y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1548810f-0d74-4833-a3a0-92b9ff116e67%2F0fd230a4-dc4c-4cef-9c72-0f1727768de4%2Fxrt49do_processed.png&w=3840&q=75)
Transcribed Image Text:LEARN MORE
REMARKS In part (a), note that cos (-0) = cos 0; however, sin (-0) = -sin 0. The negative sign of Ay
reflects the fact that displacement in the y-direction is downward.
QUESTION What other functions, if any, can be used to find the angle in part (b)? (Select all that
apply.)
0 = cos
0 = COS
0 =
0 =
-1
-1
sin-1
0 = cos
sin-1
B
B
Bx
2
X
B
у
(√²+
2
B
-1
X
B
X
(√²+0)
2
B + B.
X
y
+ B
By
2
2
Bx + By
B + B
2
у
none of those listed
2
y
2
y
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