Leaming Goal:To calculate the rms speed and relative rates of effusion of gas molecules.In a given sample of gas, the particles move at varying speeds. The rootmean square speed (ms speed) of particles in a gas sample, u, is given byPart ACalculate the rms speed of an oxygen gas molecule, O2. at 29.0 °C.the formulaExpress your answer numerically in meters per second.3RTM• View Available Hint(s)where T is the Kelvin temperature, M is the molar mass in kg/mol, andR= 8.314 J/(mol - K) is the gas constant. Effusion is the escape of gasmolecules through a tiny hole into a vacuum. The rate of effusion of a gas isdirectly related to the rms speed of the gas molecules, so it's inverselyproportional to the square root of its mass. The rms speed is related tokinetic energy, rather than average speed, and is the speed of a moleculepossessing a kinetic energy identical to the average kinetic energy of thesample. Given its relationship to the mass of the molecule, you canconclude that the lighter the molecules of the gas, the more rapidly iteffuses. Mathematically, this can be expressed asTemglates Symbols undo redo feset keyboard shortcuts heipm/seffusion rate ox mThe relative rate of effusion can be expressed in tems of molecular massesTa and mg asrate of gan A effusionrate of gas Beffusion Part BRank the following gases in order of docreasing rate of effusion.Rank from the highect to lowect effusion rate. To rank iteme ac aquivalent, overlap them.> Vlow Avalable Hilnt c)NO C,HHe HArHighest rate of effusionLowest rate of affusionO The comed nanking onnol be delermied.SubmitPartCHow much faster do ammonia (NH) molocules offuse than carbon monoxidie (CO) molocules?Enter the ratio of the ratec of effusion. Expresc your anower numerioally ucing three clgnificant figures.> Vlew Avalable Hint c)undo ngo Ta kaytoard whoricul kemle of Nly effuudemrake af CO effuskonSubmit

(a) Temperature, T = 29°C = 302 KMolar mass of O2, M = 0.032 kg/molGas constant, R = 8.314 J/mol.K…

Learming Goal: Part A To calculate the ms speed and relative rates of effusion of gas molecules. In a given sample of gas, the particles move at varying speeds. The root mean square speed (ms speed) of particles in a gas sample. u, is given by the formula Calculate the ms speed of an axygen gas molecule, O2, at 29.0 °C . Express your answer numerically in meters per second. 3RT • View Available Hint(s) where T is the Kelvin temperature. M is the molar mass in kg/mol, and R=8.314 J/(mol - K) is the gas constant. Effusion is the escape of gas molecules through a tiny hole into a vacuum. The rate of effusion of a gas is directly related to the rms speed of the gas molecules, so it's inversely proportional to the square root of its mass. The rms speed is related to kinetic energy, rather than average speed, and is the speed of a molecule possessing a kinetic energy identical to the average kinetic energy of the sample. Given its relationship to the mass of the molecule, you can condlude that the lighter the molecules of the gas, the more rapidly it Temglates Symbola undo rego Test kayboard shortcuts Heip m/s ofen Mathamaticalhe thie can hea

Learming Goal: Part A To calculate the ms speed and relative rates of effusion of gas molecules. In a given sample of gas, the particles move at varying speeds. The root mean square speed (ms speed) of particles in a gas sample. u, is given by the formula Calculate the ms speed of an axygen gas molecule, O2, at 29.0 °C . Express your answer numerically in meters per second. 3RT • View Available Hint(s) where T is the Kelvin temperature. M is the molar mass in kg/mol, and R=8.314 J/(mol - K) is the gas constant. Effusion is the escape of gas molecules through a tiny hole into a vacuum. The rate of effusion of a gas is directly related to the rms speed of the gas molecules, so it's inversely proportional to the square root of its mass. The rms speed is related to kinetic energy, rather than average speed, and is the speed of a molecule possessing a kinetic energy identical to the average kinetic energy of the sample. Given its relationship to the mass of the molecule, you can condlude that the lighter the molecules of the gas, the more rapidly it Temglates Symbola undo rego Test kayboard shortcuts Heip m/s ofen Mathamaticalhe thie can hea

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Please good handwriting and clear ideas explaining the process! c) What do you expect for the equilibrium temperature if you plan to place windows on the submarine? Is it possible that it stays the same? Explain your answer qualitatively.
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part c
Setting up the math for a two-step quantitative problem • 3/5 Gael v It takes 3.83 J of heat to raise the temperature of Object A by 1 °C, and 4.84 J to raise the temperature of Object B by 1 °C. Suppose A and B are brought into contact. A is initially hotter. A is seen to cool down by 7.2 °C. How would you calculate the rise in temperature of B? Show math work
Hello please help me answer this physics question attached below
Solve part- a& b
TOPIC: Classical thermodynamics
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