An object at 400 K absorbs 25.0 kJ of heat from the surroundings. What is the change in entropy AS of the object? Assume that the temperature of the object does not change appreciably in the process. Express your answer numerically in joules per kelvin. ? AS = J/K Submit Request Answer Part G Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at 500 K. What is the net change in entropy ASsys of the system? Assume that the temperatures of the objects do not change appreciably in the process. Express your answer numerically in joules per kelvin. ΑΣφ ? ASsys = J/K

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onstants
Learning Goal:
An object at 400 K absorbs 25.0 kJ of heat from the surroundings. What is the change in entropy AS of the object?
Assume that the temperature of the object does not change appreciably in the process.
To understand the meaning and applications of the
second law of thermodynamics, to understand the
meaning of entropy, and perform some basic
calculations involving entropy changes.
Express your answer numerically in joules per kelvin.
The first law of thermodynamics (which states that
energy is conserved) does not specify the direction
in which thermodynamic processes in nature can
spontaneously occur. For example, imagine an
object initially at rest suddenly taking off along a
rough horizontal surface and speeding up (gaining
kinetic energy) while cooling down (losing thermal
energy). Although such a process would not violate
conservation of energy, it is, of course, impossible
and could never take place spontaneously.
?
AS =
J/K
Submit
Request Answer
The second law of thermodynamics dictates which
processes in nature may occur spontaneously and
which ones may not. The second law can be stated
in many ways, one of which uses the concept of
entropy.
Part G
Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at
500 K. What is the net change in entropy ASsys of the system? Assume that the temperatures of the objects do not
change appreciably in the process.
Express your answer numerically in joules per kelvin.
ΑΣφ
?
ASsys
J/K
Transcribed Image Text:onstants Learning Goal: An object at 400 K absorbs 25.0 kJ of heat from the surroundings. What is the change in entropy AS of the object? Assume that the temperature of the object does not change appreciably in the process. To understand the meaning and applications of the second law of thermodynamics, to understand the meaning of entropy, and perform some basic calculations involving entropy changes. Express your answer numerically in joules per kelvin. The first law of thermodynamics (which states that energy is conserved) does not specify the direction in which thermodynamic processes in nature can spontaneously occur. For example, imagine an object initially at rest suddenly taking off along a rough horizontal surface and speeding up (gaining kinetic energy) while cooling down (losing thermal energy). Although such a process would not violate conservation of energy, it is, of course, impossible and could never take place spontaneously. ? AS = J/K Submit Request Answer The second law of thermodynamics dictates which processes in nature may occur spontaneously and which ones may not. The second law can be stated in many ways, one of which uses the concept of entropy. Part G Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object,which is at 500 K. What is the net change in entropy ASsys of the system? Assume that the temperatures of the objects do not change appreciably in the process. Express your answer numerically in joules per kelvin. ΑΣφ ? ASsys J/K
Constants
Learning Goal:
Part D
To understand the meaning and applications of the
second law of thermodynamics, to understand the
meaning of entropy, and perform some basic
calculations involving entropy changes.
An object at 20° C absorbs 25.0 J of heat. What is the change in entropy AS of the object?
Express your answer numerically in joules per kelvin.
The first law of thermodynamics (which states that
energy is conserved) does not specify the direction
in which thermodynamic processes in nature can
spontaneously occur. For example, imagine an
object initially at rest suddenly taking off along a
rough horizontal surface and speeding up (gaining
kinetic energy) while cooling down (losing thermal
energy). Although such a process would not violate
conservation of energy, it is, of course, impossible
and could never take place spontaneously.
Hν ΑΣφ
?
AS =
J/K
Submit
Request Answer
The second law of thermodynamics dictates which
processes in nature may occur spontaneously and
which ones may not. The second law can be stated
in many ways, one of which uses the concept of
entropy.
Part E
An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy AS of the object?
Assume that the temperature of the object does not change appreciably in the process.
Express your answer numerically in joules per kelvin.
?
AS =
J/K
Transcribed Image Text:Constants Learning Goal: Part D To understand the meaning and applications of the second law of thermodynamics, to understand the meaning of entropy, and perform some basic calculations involving entropy changes. An object at 20° C absorbs 25.0 J of heat. What is the change in entropy AS of the object? Express your answer numerically in joules per kelvin. The first law of thermodynamics (which states that energy is conserved) does not specify the direction in which thermodynamic processes in nature can spontaneously occur. For example, imagine an object initially at rest suddenly taking off along a rough horizontal surface and speeding up (gaining kinetic energy) while cooling down (losing thermal energy). Although such a process would not violate conservation of energy, it is, of course, impossible and could never take place spontaneously. Hν ΑΣφ ? AS = J/K Submit Request Answer The second law of thermodynamics dictates which processes in nature may occur spontaneously and which ones may not. The second law can be stated in many ways, one of which uses the concept of entropy. Part E An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy AS of the object? Assume that the temperature of the object does not change appreciably in the process. Express your answer numerically in joules per kelvin. ? AS = J/K
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