latest Indian Johes film, Indy is supposed grenade from his car, which is going 78.0 km/h, to his enemy's car, which is going 118 km/h . The enemy's car is 16.9 m in front of the Indy's when he lets go of the grenade. throw a Part A If Indy throws the grenade so its initial velocity relative to him is at an angle of 45° above the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance. Hint: The grenade moves in projectile motion, and convert the two velocities given in the problem from km/hr to m/s. Being an excellent student of P2, Indy knows that horizontal range of the grenade must equal the distance that the enemies car is ahead at the time the grenade is thrown plus the distance the enemies car travels while the grenade is in the air. This distance is given by v_rel*t, where v_rel the relative velocity of the enemies car relative to the Indy's and tis the time in the air. Solve for time that the grenade is in the air in terms of v_0. Use the range equation to get the grenade distance as a function of v_0 Set R=(initial separation)+v_rel*t and get a 2nd order polynomial for v_0. Use quadratic equation to get v_0. This is the magnitude of the velocity vector relative to Indy. IVα ΑΣφ ? vo = 86.91 km/h

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Answer parts A and B

In the latest Indiana Jones film, Indy is supposed to throw a grenade from his car, which is going 78.0 km/h, to his enemy's car, which is going 118 km/h. The enemy's car is 16.9 m in front of Indy's when he lets go of the grenade.

**Part B**

Find the magnitude of the velocity relative to the earth.

**Hint:** Use Galileo's equation where Frame A is ground, Frame B is Indy's car, and the object of interest P is the grenade.

Use your answer in Part A for speed and given direction to calculate the x and y components of the velocity with respect to Indy's car. The velocity of Indy's car with respect to the ground is straightforward to write in x and y components.

\[ v_0 = \, \_\_ \] km/h

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Transcribed Image Text:In the latest Indiana Jones film, Indy is supposed to throw a grenade from his car, which is going 78.0 km/h, to his enemy's car, which is going 118 km/h. The enemy's car is 16.9 m in front of Indy's when he lets go of the grenade. **Part B** Find the magnitude of the velocity relative to the earth. **Hint:** Use Galileo's equation where Frame A is ground, Frame B is Indy's car, and the object of interest P is the grenade. Use your answer in Part A for speed and given direction to calculate the x and y components of the velocity with respect to Indy's car. The velocity of Indy's car with respect to the ground is straightforward to write in x and y components. \[ v_0 = \, \_\_ \] km/h [Submit Button] [Request Answer Link]
**Projectile Motion Problem Involving Relative Velocity**

In a scene from the latest Indiana Jones film, Indy needs to throw a grenade from his car, moving at 78.0 km/h, towards an enemy's car that is traveling at 118 km/h. The enemy's car is 16.9 meters ahead of Indy's when he throws the grenade.

### Problem Details:

**Objective:**  
Determine the magnitude of the initial velocity of the grenade if its angle relative to Indy is 45° above the horizontal. The cars travel on a level road in the same direction, and air resistance can be ignored.

**Hint and Steps to Solve:**  
1. **Projectile Motion Analysis:**  
   - Convert the car speeds from km/h to m/s for calculations.
   
2. **Horizontal Range Condition:**  
   - The horizontal range that the grenade covers must equal the ground distance between the two cars when the grenade is airborne.

3. **Time Calculation:**  
   - Express the time the grenade is in the air as a function of its initial velocity \((v_0)\).

4. **Range Equation Utilization:**  
   - Use the range equation to express grenade distance covered as a function of \(v_0\).

5. **Relative Motion Equation:**  
   - Use \(R = (initial \, separation) + v_{rel} \times t\) to find a quadratic polynomial in \(v_0\).  
   - \(v_{rel}\) is the relative velocity between the enemy car and Indy’s car.

6. **Solution for \(v_0\):**  
   - Apply the quadratic formula to solve for \(v_0\). This is the magnitude of the velocity vector relative to Indy.

**Entered Solution:**  
An initial velocity \(v_0 = 86.91 \, \text{km/h}\) was suggested but marked incorrect. Note that 5 attempts remain to provide a correct answer.

### Additional Notes:

- Ensure you have converted all velocity units correctly.
- Check calculations thoroughly, especially when using trigonometric components.
- The quadratic equation will involve precise algebraic manipulation to isolate \(v_0\).

Use this structured approach to refine calculations and arrive at the correct initial velocity for the projectile.
Transcribed Image Text:**Projectile Motion Problem Involving Relative Velocity** In a scene from the latest Indiana Jones film, Indy needs to throw a grenade from his car, moving at 78.0 km/h, towards an enemy's car that is traveling at 118 km/h. The enemy's car is 16.9 meters ahead of Indy's when he throws the grenade. ### Problem Details: **Objective:** Determine the magnitude of the initial velocity of the grenade if its angle relative to Indy is 45° above the horizontal. The cars travel on a level road in the same direction, and air resistance can be ignored. **Hint and Steps to Solve:** 1. **Projectile Motion Analysis:** - Convert the car speeds from km/h to m/s for calculations. 2. **Horizontal Range Condition:** - The horizontal range that the grenade covers must equal the ground distance between the two cars when the grenade is airborne. 3. **Time Calculation:** - Express the time the grenade is in the air as a function of its initial velocity \((v_0)\). 4. **Range Equation Utilization:** - Use the range equation to express grenade distance covered as a function of \(v_0\). 5. **Relative Motion Equation:** - Use \(R = (initial \, separation) + v_{rel} \times t\) to find a quadratic polynomial in \(v_0\). - \(v_{rel}\) is the relative velocity between the enemy car and Indy’s car. 6. **Solution for \(v_0\):** - Apply the quadratic formula to solve for \(v_0\). This is the magnitude of the velocity vector relative to Indy. **Entered Solution:** An initial velocity \(v_0 = 86.91 \, \text{km/h}\) was suggested but marked incorrect. Note that 5 attempts remain to provide a correct answer. ### Additional Notes: - Ensure you have converted all velocity units correctly. - Check calculations thoroughly, especially when using trigonometric components. - The quadratic equation will involve precise algebraic manipulation to isolate \(v_0\). Use this structured approach to refine calculations and arrive at the correct initial velocity for the projectile.
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