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2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 2 and K, = 4, as shown in Figure. Parallel-plates have the area A = 0.8 m². The distance is d = 0.04 m. A potential difference of AV = 24 V is applied to the circuit. a) Find the equivalent capacitance of the system. b) Find the potential AV1. (E=8.85×10-12 C²/N×m²) %3D %3D A/2 AV1 K, A/2 K2 K1 A/2 2d/3 d/3 A/2 d AV = 24 V -----

2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 2 and K, = 4, as shown in Figure. Parallel-plates have the area A = 0.8 m². The distance is d = 0.04 m. A potential difference of AV = 24 V is applied to the circuit. a) Find the equivalent capacitance of the system. b) Find the potential AV1. (E=8.85×10-12 C²/N×m²) %3D %3D A/2 AV1 K, A/2 K2 K1 A/2 2d/3 d/3 A/2 d AV = 24 V -----

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you solve a and b parts? Thanks in advance.

2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 2 and K, = 4, as shown in Figure. Parallel-plates have the area A = 0.8 m². The distance is d = 0.04 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m?) K1 A/2 AV1 K2 A/2 A d K2 | K1 K1 A/2 2d/3 d/3 K2 A/2 d AV = 24 V
Transcribed Image Text:2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants K, = 2 and K, = 4, as shown in Figure. Parallel-plates have the area A = 0.8 m². The distance is d = 0.04 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m?) K1 A/2 AV1 K2 A/2 A d K2 | K1 K1 A/2 2d/3 d/3 K2 A/2 d AV = 24 V
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