Later, Ms. McDonald ran regression analysis in two different ways by transforming the data. Each is described below with appropriate computer output and graphics. II. Log(Price) versus Age: (Computer output, scatterplot, residual plot) SE Coef 0.02881 0.003569 T. Coef 1.43723 -0.090652 Predictor 0.000 49.89 -25.40 0.000 Constant Age S = 0.0470892 R-sq = 97.74 R-Sq(adj) = 97.6

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Question: Which transformation (II. or III .) provides a better description of the relationship between car age and price? Use the information provided to briefly justify your answer .
Later, Ms. McDonald ran regression analysis in two different ways by transforming the data. Each is
described below with appropriate computer output and graphics.
II. Log(Price) versus Age: (Computer output, scatterplot, residual plot)
SE Coef
0.02881
-0.090652 0.003569
Coef
1.43723
Predictor
T
49.89 0.000
-25.40 0.000
Constant
Age
S = 0.0470892
97.65
R-Sq = 97.74
R-Sq(adj) =
梦 $
a
hp
f12
fg
f6
Transcribed Image Text:Later, Ms. McDonald ran regression analysis in two different ways by transforming the data. Each is described below with appropriate computer output and graphics. II. Log(Price) versus Age: (Computer output, scatterplot, residual plot) SE Coef 0.02881 -0.090652 0.003569 Coef 1.43723 Predictor T 49.89 0.000 -25.40 0.000 Constant Age S = 0.0470892 97.65 R-Sq = 97.74 R-Sq(adj) = 梦 $ a hp f12 fg f6
III. Log(Price) versus Log(Age)
Predictor
Constant
Coef
1.77448
SE Coef
0.07822
22.69
0.000
Log Age
-1.23359
0.09209
-13.40
0.000
S - 0.0867773
91.84
R-Sq - 92.3%
R-Sq(adj) -
Transcribed Image Text:III. Log(Price) versus Log(Age) Predictor Constant Coef 1.77448 SE Coef 0.07822 22.69 0.000 Log Age -1.23359 0.09209 -13.40 0.000 S - 0.0867773 91.84 R-Sq - 92.3% R-Sq(adj) -
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