Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:### Exploring Proportional Relationships
Consider the following table. Is the relationship proportional? Explain your answer by examining the values in the table.
| x | y |
|:----:|:-----:|
| -2 | -27 |
| 1 | 12 |
| 4 | 57 |
| 10 | 147 |
#### Analysis
To determine if the relationship between \( x \) and \( y \) is proportional, we need to check if the ratio \( \frac{y}{x} \) is constant across all pairs of values. This means the ratio should be the same for every pair \((x, y)\).
#### Calculations
1. Calculate the ratio for each pair:
- For \( x = -2 \) and \( y = -27 \): \( \frac{-27}{-2} = 13.5 \)
- For \( x = 1 \) and \( y = 12 \): \( \frac{12}{1} = 12 \)
- For \( x = 4 \) and \( y = 57 \): \( \frac{57}{4} = 14.25 \)
- For \( x = 10 \) and \( y = 147 \): \( \frac{147}{10} = 14.7 \)
Since the ratios are not the same, the relationship is not proportional.
#### Conclusion
The relationship between \( x \) and \( y \) is not proportional because the ratio of \( y \) to \( x \) is not constant across the table.
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