Lagrange's equations of motion are second order equations, the degrees of freedom for this are O 2n+2 2n+1 2n-1 2n
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- It's not incomplete.The proton is traveling at a constant speed of 5.5 × 105 m/s, and the radius of the kissing circle is 0.02 m. The mass of a proton is 1.7 × 10-27 kg. When the proton is at location A, what are the magnitude and direction (d|p→|/dt)(p^) of the parallel component of dp→/dt?Suppose Google wants to launch a surveillance satellite to invade the privacy of all their users. They need it to revolve around Earth 10.0 times a day for maximum invasive efficiency. a) Draw a free-body diagram b) What should the radius of its orbit be if we neglect the presence of the Moon? c) How fast is it traveling? G = 6.67 * 10 ^-11 N*m^2/kg^2 M earth = 5.97 * 10^24 kg
- In an inertial reference frame S there is only a uniform electric field →, →→, = 8 kVm-¹. Find the magnitude of E' and B'in the inertial reference frame S' moving with a constant velocity v relative to the frame S at an angle a = 45° to the vector E. The velocity of the frame S' is 0-6 times the velocity of light c. EA uranium ion and an iron ion are separated by a distance of ?=57.10 nm, as shown in the figure. The uranium atom is singly ionized; the iron atom is doubly ionized. Calculate the distance ? from the uranium atom at which an electron will be in equilibrium. Ignore the gravitational attraction between the particles. ?= What is the magnitude ?U of the force on the electron from the uranium ion?Q. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?
- The energy to mové a rocket (mass m) nfinitely far from the Earth (Radius R and mass M) E = jGMma 1 E = x? 2 is What escape velocity at liftoff gives an energy that equals E. RWhat is the smallest value of B that can be set up at the equator to permit a proton of speed 10 m/s to circulate around the earth? (R = 6.4× 106 m, m = 1.67 × 10² kg).been having some trouble with this problem: Michelson used rotating mirrors, similar to those shown below, to calculate the speed of light. Light is emitted from the light source, reflects from mirror surface X to the plane mirror, and then to the position of surface Z. By the time the light moves from the X to Z position, mirror surface X will have moved to the position of mirror surface Z. The light then continues to the observer. The distances from the light source and the observer to the rotating mirrors are negligible. The distance from the rotating mirrors to the plane mirror is 35.0 km.If the mirrors are rotating at 480 rev/s, the speed of light calculated from the given information is