Labels on 1-gallon cans of paint usually indicate the drying time and the area that can be covered in one coat. Most brands of paint indicate that, in one coat, a gallon will cover between 350 and 500 square feet, depending on the texture of the surface to be painted. One manufacturer, however, claims that a gallon of its paint will cover 450 square feet of surface area. To test this claim, a random sample of twenty 1-gallon cans of white paint were used to paint 20 identical areas using the same kind of equipment. The sample mean and sample standard deviation are: x=445.8 and s=47.5.Test using a = .05 a) If you were the manufacturer and wanted to make sure that your claim that a gallon of its paint will cover 450 square feet of surface area. what null hypothesis and alternate hypothesis would you test? H.:. H: b) What is the test statistic and critical value? c) What conclusion can you draw?

Compute the cross-sectional area of the grooved block shown. Round the answer to 1 decimal place.

The numerical value of the volume of a cube equals the numerical value of its total surface area. What is the length of each edge of the cube?

If mKL=146* and mLM=68*, Find m

STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 4 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920   We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate ? by giving a 98% confidence interval. SOLVE: Find the sample mean ?¯ . (Enter your answer rounded to the nearest whole number.) ?¯=     Give a 98% confidence interval, [???,ℎ??ℎ] , for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) ???=…

STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 44 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920   We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate μ by giving a 95% confidence interval. SOLVE: Find the sample mean x¯ . (Enter your answer rounded to the nearest whole number.) x¯=     Give a 95% confidence interval, [low, high] , for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) low=…

Compute MSE by dividing SSE by dfe?

volume

3) Find the shaded region, if z = .19

A dairy company must maintain strict oversight on the weight of a box of yogurt they sell to customers. Their current advertisement specifies between 290 and 310g per bottle of yogurt. The company collected 15 bottles of yogurt to measure their weight. The weight (gram) of each bottle are shown as follows.