### Lab Report #6-2-4: ### 0.1 M Na₃PO₄ Solution, Using the Given pH Data, Calculate the Value of (Ka or Kb)**Multiple Choice Options:**1. 1.0 x 10⁻⁴2. 6.2 x 10⁻⁵3. 6.2 x 10⁻⁴4. 1.0 x 10⁻⁵---#### Explanation:The goal of this lab report is to determine the value of the acid dissociation constant (Ka) or the base dissociation constant (Kb) for a 0.1 M solution of sodium phosphate (Na₃PO₄) using the provided pH data. The result should be one of the given multiple-choice options.1. **1.0 x 10⁻⁴**2. **6.2 x 10⁻⁵**3. **6.2 x 10⁻⁴**4. **1.0 x 10⁻⁵**> To solve this, use the pH data and the formula for calculating Ka or Kb. Apply the concentrations and related equations according to the provided conditions. The correct answer will be among the options listed.This multiple-choice question is a part of a series of exercises meant to facilitate the understanding of chemical equilibria in solutions, specifically focusing on weak acids and bases and their dissociation constants. ### pH Values of Various SolutionsThe following table displays the pH values of different solutions, both common and chemical, and provides insight into their acidic or basic nature. | **Solutions** | **pH values** ||---------------------|---------------|| H₂O (unboiled) | 3.5 || H₂O (boiled) | 7.0 || NaCl | 7.0 || NaC₂H₃O₂ | 9.1 || NH₄Cl | 4.5 || NaHCO₃ | 9.5 || Na₃PO₄ | 11.9 || Na₂CO₃ | 11.0 |#### Explanation:- **H₂O (unboiled)**: pH of 3.5, indicating it is slightly acidic.- **H₂O (boiled)**: pH of 7.0, indicating neutrality.- **NaCl (Sodium Chloride)**: pH of 7.0, also neutral.- **NaC₂H₃O₂ (Sodium Acetate)**: pH of 9.1, indicating it is basic.- **NH₄Cl (Ammonium Chloride)**: pH of 4.5, indicating it is acidic.- **NaHCO₃ (Sodium Bicarbonate)**: pH of 9.5, indicating it is basic.- **Na₃PO₄ (Sodium Phosphate)**: pH of 11.9, showing it is strongly basic.- **Na₂CO₃ (Sodium Carbonate)**: pH of 11.0, indicating it is strongly basic.This table serves as an educational resource to better understand the pH scale and the nature of various common substances.

The question is based on the concept of salt hydrolysis . we have to calculate the dissociation…

Answered: Lab Report #6-2-4: 0.1 M NagPO4…

Lab Report #6-2-4: 0.1 M NagPO4 solution, using the given pH data, calculate value of (Ka or Kb) O 1.0 x 10-4 O 6.2 x 10-5 O 6.2 x 10-4 1.0 x 10-5

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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