### Educational Content:#### Electric Field Due to Charge-Carrying RodsThe image presents two charged rods:- **Rod A**: - Charge ($Q_A$): -48 nC - Length ($L_A$): 47 cm - Positioned along the X-axis- **Rod B**: - Charge ($Q_B$): -30 nC - Length ($L_B$): 24 cm - Positioned along the Y-axis, parallel to the Y-axisPoint $P$ lies on the symmetry axis of both rods, and is positioned at a distance $d = 4$ cm from the origin along the X-axis.#### Instructions:**b)** Calculate the net electric field at point $P$ due to both charged rods.**c)** Determine the magnitude of the force on an electron placed at point $P$.##### Diagram Explanation:- The diagram shows two rods—one horizontal (red) and one vertical (purple).- The horizontal rod $A$ is at a distance $d$ to the right of the origin and extends further in the positive X-direction.- The vertical rod $B$ extends upwards along the Y-axis from the origin.Each rod generates an electric field that affects point $P$. Calculations involve using principles of electromagnetism to sum the contributions of these fields. This setup introduces concepts of electric fields, forces, and the superposition principle in physics.

First we find linear charge density of the rod and then find electric field at point p due to…

Answered: LA-- Figure depicts two charge carying…

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