L (c) Suppose that x₁ ≥ 0 and xn+1 = √2+xn for ne N. If xnx as n→ ∞, then x = 2. What happens if x₁ > -2? -
L (c) Suppose that x₁ ≥ 0 and xn+1 = √2+xn for ne N. If xnx as n→ ∞, then x = 2. What happens if x₁ > -2? -
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
With problem C

Transcribed Image Text:2.2.8. Using the result in Exercise 2.2.5, prove the following results.
a) Suppose that 0 ≤ x1 ≤ 1 and xn+1 = 1-√√1- xn for ne N. If xn → x
2321083X3
as n→∞, then x = 0 or 1.
101 asigna
b) Suppose that x₁ > 3 and xn+1 =2 + √√xn - 2 for ne N. If xnx as
n→ ∞, then x = 3.
(c)
Suppose that x₁ ≥ 0 and xn+1 √2+xn for ne N. If xnx as
n → ∞, then x =2. What happens if x₁ > -2?
1
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