Remaining Time: 29 minutes, 42 seconds.v Question Completion Status:L A Moving to another question will save this response.Question 1"For the oscilloscope, if there are 10 divisions on the horizontal scale, then time window will be"Horizontal scale factor x 10NivisionsHorizontal scale factor + 10 divisionsHorizontal scale factorNone of these5A Moving to another question will save this response.U Assignment2_2018.pdfDouble-wishbone-..jpg81A5TJZNNXL_SL1.FL21 P..

It is asked for an oscilloscope if there are 0 divisions in horizontal scale, then time window will…

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surface, denoted by “g”. In this imaginary experiment, you have measured g three times. The values you obtain are: g1 = 10.2 meters per second squared (m/s2) g2 = 10.4 m/s2 g3 = 10.0 m/s2 To find the Average Value of g, denoted by gav, simple add up the experimental values and divide by the number of experimental values you have: g1 + g2 + g3 10.2 + 10.4 + 10 gav = __________ = ____________ = 10.2 m/s2 . 3 3 Percent Error (PE) To find the Percent Error (PE), you compare the average experimental value to the standard or handbook value of the physical quantity you are measuring. The Standard Value of gravitational acceleration at Earth’s surface , gst, is 9.8 m/s2. Mathematically, PE is defined as: (Average - Standard)…
Post-Lab Homework Problems. 1. A student is using a track photogate to determine the time it takes her to run 50 meters. She records the following times: Trial Time (seconds) 1 5.420 5.464 3 5.728 4 5.496 5 5.644 6. 5.794 7 5.540 The data she collects has a mean of 5.583714 seconds, with an absolute uncertainty computed to be 0.141074 seconds. Report her 50-meter time as a confidence interval (a) using the mean and the absolute uncertainty given above. Another student measures his 200-meter run time (b) to be 20.7 + 0.3 seconds. Report the relative uncertainty of each student and identify which has the more precise run time.
The dimensional equivalence of the quantity "momentum" in terms of the fundamental quantities (mass, length, time) is: O MLT¹ Ob-ML²T-2 OC. MLT. Od MLT 2
I have asked kindly for answers to be in a manner that I understand. i do not understand Physics. Please explain to me what this is supposed to be in terms that I understand. Thank You. Pi=Pf0=4×10-3×v+6.82×-0.254×10-3×v=6.82×0.25v=6.82×0.254×10-3v=426.25 m/s
1. Use the data of three trials with the launcher in a horizontal position to determine average, standard deviation and uncertainty of both time and range. Table 1: Trial Time t_(s) Range Ax_(m) 1 0.2049 0.963 0.2114 0.972 3. 0.2083 1.009 Average 0.2082 0.981 Standard deviation Uncertainty Check: Measure the height of ncher H with your ruler: H = 21.4 cm calculate the theoretical time of flight: Is the above value in good agreement with the average time from table 1? Explain. 2. Using the data in Table 1 calculate the initial speed vo= Axevezse/toveurs Initial speed Xe= (units:
1. Consider two time interval measurements: t1 = 0.84±0.8 sec and t2 = 0.96 ± 0.8 sec. Considering their uncertainties, can you conclude that the two measurements are the same? Explain.