1. Consider two time interval measurements: t1 = 0.84±0.8 sec and t2 = 0.96 ± 0.8 sec. Considering their uncertainties, can you conclude that the two measurements are the same? Explain.
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A: Given: g =e2f4-h2ie = 7.83±0.04f = 0.204±0.007h = 14.14±0.05i = 3.99±0.03
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A: d = 50±0.1 cm t0 = 0.052±0.001 s s = 10±0.05 cm
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A: (6.6x10^2)/(2.0x10^-7) = 3.3x10^9
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Q: 1. Consider two time interval measurements: t1 0.84 + 0.08 sec and t2 0.96 ±0.08 sec. %3D %3D…
A: In this question we have to conclude the measurements of the two time intervals at the same time.…
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- B-2. Consider y = A sin(at), which is a function of A, and t, where A = (2.054 ± 0.012)m, w = (2735+8) s¹ and t = (0.000341 +0.00015)s. Find y with the appropriate uncertainty.Assume your hair grows at a rate of 1/44th of an inch per day. How fast is that in nm/s (nanometers per second)? Given that a typical atom is on the order of 1 x 10^(-10) m in diameter (see Table 1.3 on page 18 of the textbook), at approximately what rate does the protein synthesis that assembles your hair strands deposit atoms in units of atoms per second? I need the second question to be rounded to 1 significant digit.Pls help and show all steps ASAP ASAP ASAP ASAP
- QUESTION 1 You have obtained the following data in the lab: Time (s) - X axis Position (m) - Y axis 43 128 48 120 56 135 61 143 67 141 70 152 The correlation coefficient r for the data obtained is [Note: Roundr to three deciimal places.] O 0.798 0.978 -0.897 0.8974. The one-particle speed distribution, Ø₁(u) is given by an expression $1 ₁(v) = 4π =4(2mm) Derive an expression for (i) most probable speed. (mp) (ii) ensemble average speed. (iii) root mean square speed. 3/2 v²e-mu²/2kT 2k (iv) compare these three speed values. 8kT MIT (v) mean inverse speed. V(89) X 0 馄.all 89% 12:40 PM Homework 1 PHYs 2100-09-LAB, SPRING 2019 NAME CIN Question 1. A bird flies a distance of d- 150+3 m during a time 20.0+1.0 s The average speed of the bird is u-d/t = 7.5 m/s. what is the uncertainty of u? Question 2. Suppose that we're able to eliminate the uncertainty in our time mea- surement so that t = 20.0 ±0.0 s. What is the new uncertainty of u?
- Question 1 Make the conversion of 2.4 Km/h2 to m/s2. O 6.67 E(-4) 1.85 E(-4) 1.85 E(-7) 0.67 1.5 Question 2 In solving a physics problem you end up with m in the numerator and m/s in the denom units for your answer are O m/s O m^2/s O m O 1/s Question 3I1:00:00 PM Problem 3: Suppose the speed of light were only 3000.0 m's. A jet fighter moving toward a target on the ground at 810 m/s shoots bullets, each having a muzzle velocity of 1050 m's. Randomized Variables v-810 m/s v2 1050 m's ed What is the velocity of the bullets relative to the target in km's? Grade Sommary Deductions 0% Potential 100%In the expression ?=2???‾‾‾√T=2πmk ?m has dimensions of mass and ?k has dimensions of mass divided by time squared. What are the dimensions of ?T ? mass2mass2 time/masstime/mass mass/timemass/time time2time2 time
- Can you please explain how to solve the uncertainty for this problem. I previously asked the same question but the answer for the uncertainty i was given is wrong +/- 0.005593) The radial acceleration, a, of a body rotating in a circle of radius r at constant speed v is given by v2 a = If v = (3.00±0.05) m/s and r= (1.5±0.1) m, a) calculate a, b) the maximum values of a, c) minimum values of a, d) the uncertainty in a.Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2axv2=v02+2ax. The problem requires solving for xx, and the known values for the system are a=2.55meter/second2a=2.55meter/second2, v0=21.8meter/secondv0=21.8meter/second, and v=0meter/secondv=0meter/second. Perform the next step in the analysis.