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KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar! 50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH. The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M Calculate the concentration of acetic acid in the ORIGINAL vinegar solution Give your answer in g/L MM CH3COOH = 60.05 g/mol (remember to consider the number of significant figures in your answer) 15| ΑΣΦ ? g/L

KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar! 50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH. The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M Calculate the concentration of acetic acid in the ORIGINAL vinegar solution Give your answer in g/L MM CH3COOH = 60.05 g/mol (remember to consider the number of significant figures in your answer) 15| ΑΣΦ ? g/L

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar! 50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH. The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M Calculate the concentration of acetic acid in the ORIGINAL vinegar solution Give your answer in g/L MM CH3COOH = 60.05 g/mol (remember to consider the number of significant figures in your answer) 15] ΑΣΦ ? g/L
Transcribed Image Text:KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar! 50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH. The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M Calculate the concentration of acetic acid in the ORIGINAL vinegar solution Give your answer in g/L MM CH3COOH = 60.05 g/mol (remember to consider the number of significant figures in your answer) 15] ΑΣΦ ? g/L
Expert Solution
Step 1

Given : 

Initial volume of vinegar sample = 50 ml 

Volume of vinegar sample after dilution = 500 ml 

Volume of diluted  vinegar sample used in titration = 25 ml 

Concentration of diluted vinegar sample = 0.2171 M 

Molar mass of CH3COOH = 60.05 g/mol 

 

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