Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Kindly refer to the attached picture.

Transcribed Image Text:Calculate the number of pounds of CO, released into the atmosphere when a 20.0 gallon tank of gasoline is burned in an
automobile engine. Assume that gasoline is primarily octane, C,H1g, and that the density of gasoline is 0.692 g · mL-!. This
assumption ignores additives. Also, assume complete combustion.
CO, released:
Ib
Expert Solution

Step 1
Given that density of gasoline = 0.692 g/ mL that means the mass of 1 mL of gasoline is 0.692 grams.
Also given volume of gasoline = 20.0 gallon
1 gallon of gasoline = 4546.09 mL of gasoline
therefore, 20.0 gallon of gasoline = 20*4546.09 = 90921.8 mL of gasoline
20.0 gallon of gasoline = 90.9 L of gasoline
At STP conditions, 1.0 mol of gasoline = 22.4 liters of gasoline
therefore, 90.9 liters of gasoline = 90.9/22.4 = 4.059 mol of gasoline
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