Keq (PKapr CH3-C-OH H2N-C2H5 + CH3-C-o H3N-C2H5 + pka = 5 pKa = 11 log Keg = 11 - 5 = 6 or Keq = 106 ; Keq > 1 (favors in the forward reaction) NH4* + H20 pKa = 9 NH3 + H3O* pKa = -2 log Keq = -2 - 9 = -11 Keg = 10-11 Keg < 1, reaction favored in the reverse direction, %3D Try Write the product of the following acid base reactions. Also calculate the Keq for each reaction T. Ö + HCI: CH;CH2ÖH + CH3LI OH t CHq Li Ž NõLi t CH Chapter 5- Chemical Reactions and Mechanisms (307 Fall 2020) KSethi

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CH3-C-OH
Keq
+
H2N-C2H5
CH3-C-o
H3N-C2H5
+
pka = 5
pKa = 11
or Keq = 106 ; Keq > 1 (favors in the forward reaction)
%3D
PA
log Keq = 11 - 5 = 6
NH4* + H20
pka = 9
NH3 + H3O*
pKa = -2
%3D
log Keq = -2 - 9 = -11
Keg = 10-11 Keg < 1, reaction favored in the reverse direction,
Try: Write the product of the following acid base reactions. Also calculate the Keq for each reaction P
+ HCI:
CH3CH,ÖH + CH3LI
OH t CHq Li
2 NõLi t CH
Chapter 5- Chemical Reactions and Mechanisms (307 Fall 2020) KSethi
Transcribed Image Text:CH3-C-OH Keq + H2N-C2H5 CH3-C-o H3N-C2H5 + pka = 5 pKa = 11 or Keq = 106 ; Keq > 1 (favors in the forward reaction) %3D PA log Keq = 11 - 5 = 6 NH4* + H20 pka = 9 NH3 + H3O* pKa = -2 %3D log Keq = -2 - 9 = -11 Keg = 10-11 Keg < 1, reaction favored in the reverse direction, Try: Write the product of the following acid base reactions. Also calculate the Keq for each reaction P + HCI: CH3CH,ÖH + CH3LI OH t CHq Li 2 NõLi t CH Chapter 5- Chemical Reactions and Mechanisms (307 Fall 2020) KSethi
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