Keq= (0.032M)? డరె (GC) %3D i.024x10-3 8.96x107= 1143 = 1143 2. The Keq for the reaction 2HIG) → H2(0) + I2(0) has a value of 1.85×102 at 425°C. If 0.18 mol of HI is placed in a 2.0L flask and allowed to come to equilibrium at this temperature, what will the equilibrium [I2] be? All gas 2HI > H2+ Iz heg=l083x10-2

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Is question 2 right?
O.0080M
O:014M
O.032M
Keq=(0.032M)?
i.024x10-3
8.96x107= 1143
Keq=1143
2. The Keq for the reaction 2HIG) → H26) + Izlo) has a value of 1.85x10-2 at
425°C. If 0.18 mol of HI is placed in a 2.0L flask and allowed to come to
equilibrium at this temperature, what will the equilibrium [I2] be?
All gas
2HI <←> ト2+I2
Jっ5x6-2-/
Uo.oa-スア
O.1360143%3
2.002241323-0.272029x= \se
-2x
+6.27202ax
O012241323 1X 0.2720290C
E O.09-2x
0.012241323=1.272929s<
1ス42029
S=9.62x10-w て
Transcribed Image Text:O.0080M O:014M O.032M Keq=(0.032M)? i.024x10-3 8.96x107= 1143 Keq=1143 2. The Keq for the reaction 2HIG) → H26) + Izlo) has a value of 1.85x10-2 at 425°C. If 0.18 mol of HI is placed in a 2.0L flask and allowed to come to equilibrium at this temperature, what will the equilibrium [I2] be? All gas 2HI <←> ト2+I2 Jっ5x6-2-/ Uo.oa-スア O.1360143%3 2.002241323-0.272029x= \se -2x +6.27202ax O012241323 1X 0.2720290C E O.09-2x 0.012241323=1.272929s< 1ス42029 S=9.62x10-w て
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