Kepler's Three Laws A geostationary orbit is a circular orbit directly above the Earth's equator approximately 36,000 km above the ground. Any point on the equator plane revolves about the Earth in the same direction and with the same period as the Earth's rotation. The period of the satellite is one day or approximately 24 hours. Use Me = 5.9742 x 1024 kg and Re = 6,371 km. Find the velocity of the satellite in orbit. a. b. 3217.634528 m/s 3065.662511 m/s C. d. Human-made satellites typically orbits at heights of 400 miles from the surface of the Earth (about 640 kilometers, or 6.4 x 105 meters) and Re = 6,371 km. What is the velocity of such a satellite? a. 7541.402252 m/s b. 7451.402252 m/s 3127.512562 m/s 3067.663598 m/s C. d. 7341.402252 m/s 7431.402252 m/s
Kepler's Three Laws A geostationary orbit is a circular orbit directly above the Earth's equator approximately 36,000 km above the ground. Any point on the equator plane revolves about the Earth in the same direction and with the same period as the Earth's rotation. The period of the satellite is one day or approximately 24 hours. Use Me = 5.9742 x 1024 kg and Re = 6,371 km. Find the velocity of the satellite in orbit. a. b. 3217.634528 m/s 3065.662511 m/s C. d. Human-made satellites typically orbits at heights of 400 miles from the surface of the Earth (about 640 kilometers, or 6.4 x 105 meters) and Re = 6,371 km. What is the velocity of such a satellite? a. 7541.402252 m/s b. 7451.402252 m/s 3127.512562 m/s 3067.663598 m/s C. d. 7341.402252 m/s 7431.402252 m/s
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter10: Motion In A Noninertial Reference Frame
Section: Chapter Questions
Problem 10.20P: Calculate the effective gravitational field vector g at Earths surface at the poles and the equator....
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