Kepler 3rd law:    M1 + M2 = P2/D3   If the two stars orbit in such a way as the big star is 4 AU from the center of mass and the smaller star is 12 AU from the center of mass. Calculate the mass of each star in the system. (hint: M1d1 = M2d2)

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A: The expression for the Kepler’s third law is as follows: MA+MB=a3p2                               1

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