Based on your radial velocity curve, record the orbital period P in days. This is the time elapsed between two subsequent peaks or troughs on the curve. P = _________________________ days Based on your radial velocity curve, record the maximum radial velocity, vmax, of the star in meters per second (m/s). vmax = _________________________ m/s

Based on your radial velocity curve, record the orbital period P in days. This is the time elapsed between two subsequent peaks or troughs on the curve. P = _ days Based on your radial velocity curve, record the maximum radial velocity, vmax, of the star in meters per second (m/s). vmax = _ m/s

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What is the apparent magnitude of the sun as seen from Saturn about 10 AU away? Appear to magnitude of Saturn =
A star is observed to have a parallax of 0.0015". What is the distance to the star in units of AU?
The Algol binary system consists of a 3.7 Msun star and a 0.8 Msun star with an orbital period of 2.87 days. Using Newton’s version of Kepler’s Third Law, calculate the distance, a, between the two stars. Compare that to the size of Betelgeuse (you’ll need to look that up). Newton’s Version of Kepler’s Law: (M1 + M2) P2 = (4p2 /G) a3 Rearrange the equation to solve for a. Pi, p, is equal to 3.14. IMPORTANT NOTE: Google the value of G (the Universal Gravitational Constant) or look it up in your text. NOTICE THE UNITS. You must convert every distance and time in your equation to the same units, otherwise, you’ll get an incorrect answer. That means you must convert distances to meters, solar masses to kilograms, and time to seconds. When you compare your value to the size of Betelgeuse, it will also help that they are in the same units.
B6
What is the parallax of a star that is 150 pc from Earth?
Assume that there are 2 stars - Aqua and Ruby. They are in orbit around a massive star which is named as Star Ai that has a mass 5.98 x 1028 kg. The orbit of Ruby is circle and has a period of 1.430 yrs. The orbit of Aqua is an ellipse. At its periapsis, the distance of Star Aqua is twice as far from Star Ai than Star Ruby is. Solve how far is Star Aqua's apoapsis if Star Aqua is considered 3.250 times faster in periapsis than in apoapsis. Note: You can ignore the gravitational interaction that exists between Star Aqua and Star Ruby. Use the figure to understand the problem better. Aqua periapsis Choices: a. 1.9x10¹¹ m b. 3.8x10¹1 m c. 3.6x10¹0 m d. 1.2x10¹¹ m Ruby Ai apoapsis
The Algol binary system consists of a 3.7 Msun star and a 0.8 Msun star with an orbital period of 2.87 days. Using Newton’s version of Kepler’s Third Law, calculate the distance, a, between the two stars. Compare that to the size of Betelgeuse (you’ll need to look that up). Newton’s Version of Kepler’s Law: (M1 + M2) P2 = (4p2 /G) a3 Rearrange the equation to solve for a. Pi, p, is equal to 3.14. IMPORTANT NOTE: Google the value of G (the Universal Gravitational Constant) or look it up in your text. NOTICE THE UNITS. You must convert every distance and time in your equation to the same units, otherwise, you’ll get an incorrect answer. That means you must convert distances to meters, solar masses to kilograms, and time to seconds. When you compare your value to the size of Betelgeuse, it will also help that they are in the same units.
I attempted to answer this question and I'm not sure what I am doing wrong. My formula says A.S. = 206265 (separation/distance from observer) I know to convert to the same units, so I ended up with 80 Million Km being 8 x 10 ^ -6 LY Could you please explain each step especially for the part that I got wrong for both A and B?
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