k=61 N/m2.8 mThe 6.0 kg bar is released from rest at an angleof 0₁ = 25°. The spring attached to the top of thebar was unstretched when the bar was vertical.i) Find the change of the bar's gravitationalpotential energy as it falls to 0₂ = 35°.Vg.2 - Vg1 =ii) Find the change of the spring's potentialenergy as it falls to 0₂ = 35°.Vsp.2 - V sp,1 =iii) Write an equation relating the speed of thebar's center to its angular speed at 0₂ = 35°.v(w) =iv) Find the angular speed of the bar when itreaches 0₂ = 35°.W₂ =

General Approach to Solving Linear Equations:Identify the variable: The variable is the unknown…

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