K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. Frequency A. 285291 Relative Frequency O A. 1 4 7 10 13 16 Number of Customers. 0.6- 0.5- 0.4 0.3 0.24 0.14 0- (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 10 or more customers waiting for a table at 6:00 P.M.? % (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. 4 7 10 13 16 Number of Customers % (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 12 or fewer customers waiting for a table at 6:00 P.M.? B. Frequency Relative Frequency ... B. 0.6- 0.5- 0.4- 0.1- 0- 4 7 10 13 16 Number of Customers Jalalal Frequency 9 C. 11 1 4 7 10 13 16 Number of Customers 4 7 10 13 16 Number of Customers. (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. 10 C. Relative Frequency 13 8 8 5 10 6 11 6 11 10 9 6 9 3 3 6 7 8 10 5 6 7 0.64 0.5- 0.4- 0.3- 0.2- 0.13 0- 4 7 10 13 16 Number of Customers O D. Q Frequency 5 8 D. 8 7 7 Relative Frequency oooooo 6 30 7 9 6 10 8 12 9 6 4 7 10 13 16 Number of Customers 0- 4 7 10 13 16 Number of Customers (h) Describe the shape of the distribution. Choose the correct answer below. O A. The distribution is skewed right because the right tail is longer than the left tail. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is symmetric because the bars in the histograms are all approximately the same height. O D. The distribution is skewed left because the left tail is longer than the right tail. E. The distribution is symmetric because the left and right sides are approximately mirror images. OF. The distribution is skewed right because the left tail is longer than the right tail. Q ON
K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. Frequency A. 285291 Relative Frequency O A. 1 4 7 10 13 16 Number of Customers. 0.6- 0.5- 0.4 0.3 0.24 0.14 0- (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 10 or more customers waiting for a table at 6:00 P.M.? % (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. 4 7 10 13 16 Number of Customers % (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 12 or fewer customers waiting for a table at 6:00 P.M.? B. Frequency Relative Frequency ... B. 0.6- 0.5- 0.4- 0.1- 0- 4 7 10 13 16 Number of Customers Jalalal Frequency 9 C. 11 1 4 7 10 13 16 Number of Customers 4 7 10 13 16 Number of Customers. (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. 10 C. Relative Frequency 13 8 8 5 10 6 11 6 11 10 9 6 9 3 3 6 7 8 10 5 6 7 0.64 0.5- 0.4- 0.3- 0.2- 0.13 0- 4 7 10 13 16 Number of Customers O D. Q Frequency 5 8 D. 8 7 7 Relative Frequency oooooo 6 30 7 9 6 10 8 12 9 6 4 7 10 13 16 Number of Customers 0- 4 7 10 13 16 Number of Customers (h) Describe the shape of the distribution. Choose the correct answer below. O A. The distribution is skewed right because the right tail is longer than the left tail. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is symmetric because the bars in the histograms are all approximately the same height. O D. The distribution is skewed left because the left tail is longer than the right tail. E. The distribution is symmetric because the left and right sides are approximately mirror images. OF. The distribution is skewed right because the left tail is longer than the right tail. Q ON
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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