One hundred students in a statistics course kept track of the time they spent on social media over the weekend. Each student recorded his or her time rounded to the nearest minute, so each observation is a whole number. The data are presented in the form of a frequency histogram. 20 15 12 10- 120 I50 I80 210 Minutes on social media Each interval on the histogram contains the left endpoint, except for the last bar, which contains both the left and right endpoints. Give the lower and upper bound for the median number of minutes spent on social media over the weekend by the students enrolled in the class. The lower bound is the largest number that is less than or equal to the median, and the upper bound is the smallest number that is greater than or equal to the median. lower bound = 60 upper bound = 85 Kouanbaag

One hundred students in a statistics course kept track of the time they spent on social media over the weekend. Each student recorded his or her time rounded to the nearest minute, so each observation is a whole number. The data are presented in the form of a frequency histogram. 20 15 12 10- 120 I50 I80 210 Minutes on social media Each interval on the histogram contains the left endpoint, except for the last bar, which contains both the left and right endpoints. Give the lower and upper bound for the median number of minutes spent on social media over the weekend by the students enrolled in the class. The lower bound is the largest number that is less than or equal to the median, and the upper bound is the smallest number that is greater than or equal to the median. lower bound = 60 upper bound = 85 Kouanbaag

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please do not give solution in image format thanku A car salesman collected data on how many cars were sold at a dealership per day for two weeks. The results were as follows: 6, 7, 4, 3, 1, 2, 6, 6, 6, 7, 4, 4. Make a frequency table and then make a histogram based on that frequency table. What is the shape of the distribution? O Skewed to the right O Skewed to the left O Bimodal O Symmetrical
Refer to table to answer question.
Hmm.115.
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