K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (a) Are these data discrete or continuous? Explain. Number of Customers 1-3 4-6 7-9 Frequency 10-12 13-15 OA. The data are discrete because it was recorded for 40 consecutive Saturdays. OB. The data are discrete because there are a finite or countable number of values. OC. The data are continuous because it was recorded for 40 consecutive Saturdays. OD. The data are continuous because there are a finite or countable number of values. (b) Construct a frequency distribution of the data. A. Relative Frequency A. Frequency (c) Construct a relative frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. 4 7 10 13 16 Number of Customers 0.6 Relative Frequency (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.? 65432T 0.3- 4 7 10 13 16 Number of Customers Q ||| Frequency B. Relative Frequency 28526 4 7 10 13 16 Number of Customers B. 0.6+ 6543NE Q 4 7 10 13 16 Number of Customers. Frequency 10 11 15 14 13 13 14 10 11 C. (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. Relative Frequency NOEN6Mo 13 13 10 6 7 11 10 3 8 10 C. 9 12 4 7 10 13 16 Number of Customers. 0.6+ 0.5+ 0.47 0.34 0.23 0.14 0- 9 6 4 12 7 9 9 10 8 11 9 12 (h) Describe the shape of the distribution. Choose the correct answer below. 12 7 10 13 16 Number of Customers 8 Frequency D. Relative Frequency ஈமைலமெறம் D. < 50 0.6+ 0.5+ 0.44 0.3+ 0.23 0.1- 0- 10 12 12 9 4 7 10 13 16 Number of Customers OA. The distribution is symmetric because the bars in the histograms are all approximately the same height. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is skewed left because the left tail is longer than the right tail. O D. The distribution is skewed right because the left tail is longer than the right tail. O E. The distribution is skewed right because the right tail is longer than the left tail. O F. The distribution is symmetric because the left and right sides are approximately mirror images. 7 10 13 16 Number of Customers Next

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
1:25
K
The data to the right represent the number of
customers waiting for a table at 6:00 P.M. for 40
consecutive Saturdays at Bobak's Restaurant.
Complete parts (a) through (h) below.
(a) Are these data discrete or continuous? Explain.
4-6
7-9
10-12
13-15
Frequency
(Type an integer or a decimal. Do not round.)
(f) Construct a frequency histogram
O A.
OA. The data are discrete because it was recorded for 40 consecutive Saturdays.
B. The data are discrete because there are a finite or countable number of values.
C. The data are continuous because it was recorded for 40 consecutive Saturdays.
OD. The data are continuous because there are a finite or countable number of values.
(b) Construct a frequency distribution of the data.
Number of
Customers
1-3
Relative Frequency
Frequency
10 13 16
Number of Customers
0.6
0.5
0.41
Relative
Frequency
0.3
0.2
0.1+
0-
(c) Construct a relative frequency distribution of the data.
Number of
Customers
1-3
4-6
7-9
10-12
13-15
(Type integers or decimals. Do not round.)
(d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.?
(Type an integer or a decimal. Do not round.)
(e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.?
4 7 10 13 16
Number of Customers
|||
Q
=
Q
Frequency
U
28320
O B.
Relative Frequency
10 13 16
Number of Customers
C•••
(g) Construct a relative frequency histogram of the data. Choose the correct histogram below.
0.6+
0.5-
0.4
0.3
0.2-1
0.1
0-
4 7 10 13 16
Number of Customers
of the data. Choose the correct histogram below.
Frequency
Q
O
10
15
13
11 6
14 7
13 10
14 13 13
10 11 10 10
Vol 4G. 25%
LTE2
BENG
O C.
Relative Frequency
9 12 9 6
11
4
9
12
3
8
4 7 10 13 16
Number of Customers
0.6-
0.5-
0.4
0.3
0.27
0.14
0-
(h) Describe the shape of the distribution. Choose the correct answer below.
8
1 4 7 10 13 16
Number of Customers
Frequency
12 7 10
9 10
12
11
12
12
9
8
9
Relative Frequency
O D.
1852963o
50
14 7 10 13 16
Number of Customers
0.6-
0.5-
0.4-
0.3-
0.2
0.14
0
OA. The distribution is symmetric because the bars in the histograms are all approximately the same height.
OB. The distribution is skewed left because the right tail is longer than the left tail.
OC. The distribution is skewed left because the left tail is longer than the right tail.
O D. The distribution is skewed right because the left tail is longer than the right tail.
O E. The distribution is skewed right because the right tail is longer than the left tail.
OF. The distribution is symmetric because the left and right sides are approximately mirror images.
4 7 10 13 16
Number of Customers
Next
Transcribed Image Text:1:25 K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (a) Are these data discrete or continuous? Explain. 4-6 7-9 10-12 13-15 Frequency (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram O A. OA. The data are discrete because it was recorded for 40 consecutive Saturdays. B. The data are discrete because there are a finite or countable number of values. C. The data are continuous because it was recorded for 40 consecutive Saturdays. OD. The data are continuous because there are a finite or countable number of values. (b) Construct a frequency distribution of the data. Number of Customers 1-3 Relative Frequency Frequency 10 13 16 Number of Customers 0.6 0.5 0.41 Relative Frequency 0.3 0.2 0.1+ 0- (c) Construct a relative frequency distribution of the data. Number of Customers 1-3 4-6 7-9 10-12 13-15 (Type integers or decimals. Do not round.) (d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 9 or fewer customers waiting for a table at 6:00 P.M.? 4 7 10 13 16 Number of Customers ||| Q = Q Frequency U 28320 O B. Relative Frequency 10 13 16 Number of Customers C••• (g) Construct a relative frequency histogram of the data. Choose the correct histogram below. 0.6+ 0.5- 0.4 0.3 0.2-1 0.1 0- 4 7 10 13 16 Number of Customers of the data. Choose the correct histogram below. Frequency Q O 10 15 13 11 6 14 7 13 10 14 13 13 10 11 10 10 Vol 4G. 25% LTE2 BENG O C. Relative Frequency 9 12 9 6 11 4 9 12 3 8 4 7 10 13 16 Number of Customers 0.6- 0.5- 0.4 0.3 0.27 0.14 0- (h) Describe the shape of the distribution. Choose the correct answer below. 8 1 4 7 10 13 16 Number of Customers Frequency 12 7 10 9 10 12 11 12 12 9 8 9 Relative Frequency O D. 1852963o 50 14 7 10 13 16 Number of Customers 0.6- 0.5- 0.4- 0.3- 0.2 0.14 0 OA. The distribution is symmetric because the bars in the histograms are all approximately the same height. OB. The distribution is skewed left because the right tail is longer than the left tail. OC. The distribution is skewed left because the left tail is longer than the right tail. O D. The distribution is skewed right because the left tail is longer than the right tail. O E. The distribution is skewed right because the right tail is longer than the left tail. OF. The distribution is symmetric because the left and right sides are approximately mirror images. 4 7 10 13 16 Number of Customers Next
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