K SEction6.2TheBinomialDistribution... u)Tma ne povavmy or outamng iess ulai 5 Concer questions e) Find the mean, expected value, variance, and standard deviation of the above scenario.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Only need d) and e) answered 

## Section 6.2: The Binomial Distribution

### Problem Statement

a) Find the probability of obtaining less than 5 correct questions.

b) Find the mean, expected value, variance, and standard deviation of the above scenario.

### Explanation of Concepts

- **Mean (μ):** The average number of successes in the given scenario.
- **Expected Value:** Similar to the mean, it represents the long-term average if an experiment is repeated many times.
- **Variance (σ²):** Measures the spread of the data - how much the successes deviate from the mean.
- **Standard Deviation (σ):** The square root of the variance, giving a measure of the spread in the same units as the data.

### Understanding the Binomial Distribution

The binomial distribution is used when there are two possible outcomes for each trial, often termed as "success" and "failure". The distribution gives the probability of a given number of successes over a set number of trials, with the probability of success being constant for each trial.
Transcribed Image Text:## Section 6.2: The Binomial Distribution ### Problem Statement a) Find the probability of obtaining less than 5 correct questions. b) Find the mean, expected value, variance, and standard deviation of the above scenario. ### Explanation of Concepts - **Mean (μ):** The average number of successes in the given scenario. - **Expected Value:** Similar to the mean, it represents the long-term average if an experiment is repeated many times. - **Variance (σ²):** Measures the spread of the data - how much the successes deviate from the mean. - **Standard Deviation (σ):** The square root of the variance, giving a measure of the spread in the same units as the data. ### Understanding the Binomial Distribution The binomial distribution is used when there are two possible outcomes for each trial, often termed as "success" and "failure". The distribution gives the probability of a given number of successes over a set number of trials, with the probability of success being constant for each trial.
### Example 9: Binomial Distribution Quiz

#### Scenario:
A student takes the following quiz by taking random guesses.

#### Quiz Instructions:
Select the corresponding character to the corresponding number.

#### Question #1:
(Character: Three dots and an eye-like shape)
- b) 5
- b) 80
- c) 55
- d) 12
- e) 56
- f) The answer is not included.

#### Question #2:
(Character: Three dots and three lines)
- b) 5
- b) 81
- c) 55
- d) 72
- e) 56
- f) The answer is not included.

#### Question #3:
(Character: Three dots and a line)
- b) 5
- b) 81
- c) 55
- d) 72
- e) 65
- f) The answer is not included.

#### Question #4:
(Character: A line and an eye-like shape)
- a) 5
- b) 81
- c) 55
- f) The answer is not included.

#### Question #5:
(Character: An eye-like shape)
- a) 0
- b) 11
- c) 15
- d) 72
- e) 65
- f) The answer is not included.
Transcribed Image Text:### Example 9: Binomial Distribution Quiz #### Scenario: A student takes the following quiz by taking random guesses. #### Quiz Instructions: Select the corresponding character to the corresponding number. #### Question #1: (Character: Three dots and an eye-like shape) - b) 5 - b) 80 - c) 55 - d) 12 - e) 56 - f) The answer is not included. #### Question #2: (Character: Three dots and three lines) - b) 5 - b) 81 - c) 55 - d) 72 - e) 56 - f) The answer is not included. #### Question #3: (Character: Three dots and a line) - b) 5 - b) 81 - c) 55 - d) 72 - e) 65 - f) The answer is not included. #### Question #4: (Character: A line and an eye-like shape) - a) 5 - b) 81 - c) 55 - f) The answer is not included. #### Question #5: (Character: An eye-like shape) - a) 0 - b) 11 - c) 15 - d) 72 - e) 65 - f) The answer is not included.
Expert Solution
Step 1 : Given information

Here in this scenario, student takes a random guesses on his quiz. The quiz contains 5 multiple choice questions with each of the question having 6 options. Exactly one of the 6 options is correct. Hence probability that the students chooses the correct answer is 1/6. And this is same for all the 5 questions.

Let we define, X be number of correct answers in the quiz.

We observe that,

  1. The number of trials (number of questions in the quiz) are 5, which are fixed.
  2. For each trial there are only two outcomes, either answer is correct or incorrect. Let us denote success as, question answered by the student is correct.
  3. Each trial is independent of each other, since each question is answered independently.
  4. The probability of success, P(success) = 1/6, is same for each trial.

That means, X satisfies all the required conditions of binomial distribution. 

Hence X defined above follows a binomial distribution with number of trials, 5 and probability of success, 1/6.

The probability mass function for X is defined as,

P(X=x)=5x16x1-165-x   ; x =0,1,2,3,4,5.where nx=n!x! * (n-x)!

 

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