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k=-M Q2. Consider a periodic signal x(t) with fundamental periodT = n, and Fourier series representation: M 6 (-1)* el2kt ,T(1 – 4k²) x(t) = k=-M a) Plot the Fourier series coefficients ak of the signal x(1) for k = -10:10. b) Plot x(t) over the interval t= -47:0.01:4n and for the following cases: 1. M= 1 2. M=2 3. М%3100 c) Plot the signal e(t) = |3cos(t)| - x(t) for M-1,2, and 100. Comment on the results %3D

k=-M Q2. Consider a periodic signal x(t) with fundamental periodT = n, and Fourier series representation: M 6 (-1)* el2kt ,T(1 – 4k²) x(t) = k=-M a) Plot the Fourier series coefficients ak of the signal x(1) for k = -10:10. b) Plot x(t) over the interval t= -47:0.01:4n and for the following cases: 1. M= 1 2. M=2 3. М%3100 c) Plot the signal e(t) = |3cos(t)| - x(t) for M-1,2, and 100. Comment on the results %3D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Q2. Consider a periodic signal x(t) with fundamental period T = n, and Fourier series representation: M Σ 6 (-1)k T(1 – 4k2) x(t) = ej2kt k=-M a) Plot the Fourier series coefficients ak of the signal x(t) for k = -10:10. b) Plot x(t) over the interval t=-4x:0.01:4n and for the following cases: 1. M= 1 2. M= 2 3. М3D 100 c) Plot the signal e(t) = |3cos(t)| – x(t) for M=1,2, and 100. Comment on the results obtained.
Transcribed Image Text:Q2. Consider a periodic signal x(t) with fundamental period T = n, and Fourier series representation: M Σ 6 (-1)k T(1 – 4k2) x(t) = ej2kt k=-M a) Plot the Fourier series coefficients ak of the signal x(t) for k = -10:10. b) Plot x(t) over the interval t=-4x:0.01:4n and for the following cases: 1. M= 1 2. M= 2 3. М3D 100 c) Plot the signal e(t) = |3cos(t)| – x(t) for M=1,2, and 100. Comment on the results obtained.
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