In a study of 799 randomly selected medical malpractice lawsuits, it was found that 505 of them were dropped or dismissed. Use a 0.01 significancelevel to test the claim that most medical malpractice lawsuits are dropped or dismissed.Which of the following is the hypothesis test to be conducted?OA. Ho: p=0.5H₁: p<0.5OC. Ho: p=0.5H₁: p=0.5OE. Ho: p>0.5H₁: p=0.5What is the test statistic?Z=(Round to two decimal places as needed.)OB. Ho: p0.5H₁: p=0.5OD. Ho: p<0.5H₁: p=0.5OF. Ho: p=0.5H₁: p>0.5 KIn a study of 799 randomly selected medical malpractice lawsuits, it was found that 505 of them were dropped or dismissed. Use a 0.01 significancelevel to test the claim that most medical malpractice lawsuits are dropped or dismissed.Uno. p.5H₁: p=0.5O E. Ho: p>0.5H₁: p=0.5What is the test statistic?Z=(Round to two decimal places as needed.)What is the P-value?P-value =(Round to three decimal places as needed.)What is the conclusion about the null hypothesis?uu. порCU.SH₁: p=0.5OF. Ho: p=0.5H₁: p > 0.5

We have given thatn = 799x = 505p̂ = x/n = 505/799 = 0.6320Significance level (α) = 0.01

Answered: K In a study of 799 randomly selected…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

A police department released the numbers of calls for the different days of the week during the month of October, as shown in the table to the right. Use a 0.01 significance level to test the claim that the different days of the week have the same frequencies of police calls. What is the fundamental error with this analysis? a. Calculate the test statistic, chi squared .chi squared equals (Round to three decimal places as needed.) b. Calculate the P-value. P-valueequals (Round to four decimal places as needed.)
Refer to the sample data for polygraph tests shown below. If one of the test subjects is randomly selected, what is the probability that the subject is not lying? Is the result close to the probability of 0.4720.472 for a negative test result? Did the Subject Actually Lie? No (Did Not Lie) Yes (Lied) Positive test results 1414 4343 Negative test results 3737 1414 The probability that a randomly selected polygraph test subject was not lying is _____.
a. what's degrees of freedom used on the test? b. what's the Chi-Squared Test Statistic? c. true or false? at a significance level og 0.05, whether you're a baby or a toddler is independent of how many times you cry at day care.
Is there an association between hair color and body type? The table below shows the results of a researcher's observations of randomly selected people. Frequencies of Hair Colors for Various Body Types Blonde Brunette Red Head 84 98 61 110 53 49 Short and Slender Short and Pudgy Tall and Slender Tall and Heavy What can be concluded at the a = 0.05 significance level? a. What is the correct statistical test to use? O Independence O Homogeneity O Goodness-of-Fit O Paired t-test 109 107 60 80 78 63 b. What are the null and alternative hypotheses? Ho: O Hair color and body type are independent. O The distribution of hair color is the same for each body type. O Hair color and body type are dependent. O The distribution of hair color is not the same for each body type. H₁: O The distribution of hair color is not the same for each body type.
a) Which of the following is the correct test statistic for this test? b) Degrees of freedom for this test? c) P-value for this test?
Refer to the sample data for polygraph tests shown below. If one of the test subjects is randomly selected, what is the probability that the subject is not lying? Is the result close to the probability of 0.423 for a negative test result? Did the Subject Actually Lie? No (Did Not Lie) Yes (Lied) O Positive test results 15 41 Negative test results 30 11 The probability that a randomly selected polygraph test subject was not lying is (Type an integer or decimal rounded to three decimal places as needed.)
What is Ha? 1. H0 is not true 2. pyounger ≠ polder 3. polder ≠ .45 and pyounger ≠ .55 4. polder ≠ .95 and pyounger ≠ .05 5. pyounger ≠ .95 and polder ≠ .05
A random sample of employees participating in a company fitness program were asked how many days they logged an exercise activity in the past month. Their responses are reported in the histogram below.Based on the histogram above, what is the class width? Clas width = ? Days What is the sample size? Sample size = ? employees
A simple random sample of front-seat occupants involved in car crashes is obtained. Among 2976 occupants not wearing seat belts, 33 were killed. Among 7813 occupants wearing seat belts, 10 were killed. Use a 0.01 significance level to test the claim that seat belts are effective in reducing fatalities. a. Identify the test statistic. z equals (Round to two decimal places as needed.) b. Identify the P-value. P-value equals (Round to three decimal places as needed.) c. Test the claim by constructing an appropriate confidence interval. The appropriate confidence interval is less than left parenthesis p 1 minus p 2 right parenthesis less than (Round to three decimal places as needed.)
Ramos has a spinning wheel. The Spining wheel has 18 blue numbers 18 white numbers and 2 yellow numbers the table provided shows the frequency with which the ball landed on each color in 200 trials. color blue frequency 18 white frequency 18 yellow frequency 2 . At the 5% significance level do the data suggest that the wheel is out of balance?you will need to compute the expected counts to do your calculations remember that the expected counts can be computed with the formula E = np, where n is the number of trials and P is the probability of each color.
← In a random sample of males, it was found that 18 write with their left hands and 212 do not. In a random sample of females, it was found that 66 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. ✓ 1319 K H₁: P₁ OD. Ho: P₁ P₂ H₁: P₁ P₂ Identify the test statistic. Z= -2.06 (Round to two decimal places as needed.) Identify the P-value. P-value = 0.020 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? w an example Get more help. P2 The P-value is less than the significance level of a = 0.05, so males is less than that among females. b. Test the claim by constructing an appropriate confidence interval. The 90% confidence interval is Clear all : ; I d F11 { + [ option = ? Check answer 11 I } * 1
Every year during home football games the Carroll College fans do push-up contests to see how many they can do. Suppose that a curious stats student in the stands kept track of the number of push-ups completed for several students of both genders. 0.05 significance level to test the claim Males 25 13 31 23 27 17 27 31 24 18 Females 15 8 15 13 5 23 25 8 30 3 (a) What is the test statistic? ________ (b) Construct a 95% confidence interval fro the mean of the differences between males and females. __________< u < _________

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS