k = 250 lb/in. 5 = 0.15 w = 50 lb m=0.1294 Ib-sec/in. m 4g = 0.15 in. úg = 0 in./ sec Ho = 0 in. i, = 5 in./ sec Hg = 0.15 in. úo - 5 in./ sec

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System is damped single degree of freedom. There are three different initial conditions. Find equation motion for each coditions and draw graphis for each.

k = 250 Ib/in.
5 = 0.15
w = 50 lb
m = 0.1294 Ib-sec/in.
%3D
0.15 in. úg = 0 in./ sec
Mg = 0 in.
0 in.
4o = 5 in./ sec
= 0.15 in. io - 5 in./ sec
Transcribed Image Text:k = 250 Ib/in. 5 = 0.15 w = 50 lb m = 0.1294 Ib-sec/in. %3D 0.15 in. úg = 0 in./ sec Mg = 0 in. 0 in. 4o = 5 in./ sec = 0.15 in. io - 5 in./ sec
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