K = 1.8x10-28 Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-2 = 1.78x1028 was either rounded differently or used a different number of significant figures than required for this part. • Part C MnO2(s) +4 H*(ag) + Cu(s) → Mn²+ (ag) +2 H2O(!) + Cu²*(aq) Express your answer using two significant figures. K= 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining
K = 1.8x10-28 Previous Answers v Correct Correct answer is shown. Your answer 1.78-10-2 = 1.78x1028 was either rounded differently or used a different number of significant figures than required for this part. • Part C MnO2(s) +4 H*(ag) + Cu(s) → Mn²+ (ag) +2 H2O(!) + Cu²*(aq) Express your answer using two significant figures. K= 2.0 • 1045 Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
pls.helpp partC
![Part A
Calculate the equilibrium constant for each of the reactions at 25 °C.
Pb?+ (ag) + Zn(s)→ Pb(s) + Zn²+ (ag)
Standard Electrode Potentials at 25 °C
Express your answer using three significant figures.
Reduction Half-Reaction
E° (V)
K = 2.04x1021
Pb2+ (ag) + 2 e →Pb(s)
→ Zn(s)
I2(s) + 2 e →2 I¯(aq)
Cl2 (g) + 2 e → 2 Cl¯ (aq)
MnO2(s) +4 H+(aq) +2 e¯ → Mn²+(aq) + 2 H2O(1)
-0.13
Zn2+ (aq) + 2 e¯
-0.76
Submit
Previous Answers
0.54
1.36
Correct
1.21
Correct answer is shown. Your answer 2.09-10²1 = 2.09x1021 was either rounded differently or used a different number of significant figures than required for this part.
Cu?+(ag) + 2 e¯ → Cu(s)
0.16
Part B
I2(s) + 2 Cl¯ (aq) → 2I- (aq) + Cl2(g)
Express your answer using two significant figures.
K = 1.8x10-28
Submit
Previous Answers
v Correct
Correct answer is shown. Your answer 1.78-10-28 = 1.78x10-28 was either rounded differently or used a different number of significant figures than required for this part.
Part C
MnO2 (s) +4 H†(aq) + Cu(s)
→ Mn²+ (aq) + 2 H2O(1) + Cu²+ (aq)
Express your answer using two significant figures.
?
K = 2.0 • 1045
Submit
Previous Answers Request Answer
X Incorrect; Try Again; One attempt remaining](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ad9d616-2348-4325-8ae0-d78699ad9362%2F99e1a583-e2d8-4d4d-bad4-e48e7225c858%2F9ra2j8_processed.png&w=3840&q=75)
Transcribed Image Text:Part A
Calculate the equilibrium constant for each of the reactions at 25 °C.
Pb?+ (ag) + Zn(s)→ Pb(s) + Zn²+ (ag)
Standard Electrode Potentials at 25 °C
Express your answer using three significant figures.
Reduction Half-Reaction
E° (V)
K = 2.04x1021
Pb2+ (ag) + 2 e →Pb(s)
→ Zn(s)
I2(s) + 2 e →2 I¯(aq)
Cl2 (g) + 2 e → 2 Cl¯ (aq)
MnO2(s) +4 H+(aq) +2 e¯ → Mn²+(aq) + 2 H2O(1)
-0.13
Zn2+ (aq) + 2 e¯
-0.76
Submit
Previous Answers
0.54
1.36
Correct
1.21
Correct answer is shown. Your answer 2.09-10²1 = 2.09x1021 was either rounded differently or used a different number of significant figures than required for this part.
Cu?+(ag) + 2 e¯ → Cu(s)
0.16
Part B
I2(s) + 2 Cl¯ (aq) → 2I- (aq) + Cl2(g)
Express your answer using two significant figures.
K = 1.8x10-28
Submit
Previous Answers
v Correct
Correct answer is shown. Your answer 1.78-10-28 = 1.78x10-28 was either rounded differently or used a different number of significant figures than required for this part.
Part C
MnO2 (s) +4 H†(aq) + Cu(s)
→ Mn²+ (aq) + 2 H2O(1) + Cu²+ (aq)
Express your answer using two significant figures.
?
K = 2.0 • 1045
Submit
Previous Answers Request Answer
X Incorrect; Try Again; One attempt remaining
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