### Understanding Hash Tables: Quadratic Probing Example#### Introduction to Hash Tables with Quadratic ProbingIn this exercise, we will explore the concept of hash tables using quadratic probing as a collision resolution technique. #### Hash Table Definition and ConfigurationThe given hash table, referred to as `valsTable`, uses the following parameters:- A hash function defined as `key % 10`- Constant coefficients `c1 = 1` and `c2 = 1`- Quadratic probing formula: `h(k, i) = (h'(k) + c1 * i + c2 * i^2) % table_size`#### Current State of `valsTable`The hash table, `valsTable`, has 10 buckets indexed from 0 to 9. The state of the table is depicted below:```valsTable:+----+----+| 0 | 10 || 1 | || 2 | || 3 | || 4 | || 5 | || 6 | || 7 | || 8 | 38 || 9 | |+----+----+```**Legend:**- ![#D9EAD3](https://via.placeholder.com/15/D9EAD3/000000?text=+) Empty-since-start- ![#FAD7D4](https://via.placeholder.com/15/FAD7D4/000000?text=+) Empty-after-removal- ![#FFD966](https://via.placeholder.com/15/FFD966/000000?text=+) Occupied#### Insertions with Quadratic ProbingWe need to determine the buckets into which each item will be inserted using the quadratic probing technique:1. **Inserting item `38` into `valsTable`**: - Calculate initial hash: `38 % 10 = 8` - `Bucket 8` is occupied - Insert into bucket: `10`2. **Inserting item `57` into `valsTable`**: - Calculate initial hash: `57 % 10 = 7` - `Bucket 7` is empty - Insert into bucket: [ ] *(Answer box for user input)*3. **Inserting item `80` into

Given Has function is key % 10 Hence when we put key in slot we put at place of key % 10 th place.…

Jump to level 1 valsTable: o 10 1 2 3 4 5 6 7 8 9 38 Empty-since-start Empty-after-removal Occupied Hash table vals Table uses quadratic probing, a hash function of key % 10, c1 = 1, and c2 = 1. Hashinsert(valsTable, item 38) inserts item 38 into bucket Ex: 10 Hashinsert(valsTable, item 57) inserts item 57 into bucket HashInsert(vals Table, item 80) inserts item 80 into bucket

Jump to level 1 valsTable: o 10 1 2 3 4 5 6 7 8 9 38 Empty-since-start Empty-after-removal Occupied Hash table vals Table uses quadratic probing, a hash function of key % 10, c1 = 1, and c2 = 1. Hashinsert(valsTable, item 38) inserts item 38 into bucket Ex: 10 Hashinsert(valsTable, item 57) inserts item 57 into bucket HashInsert(vals Table, item 80) inserts item 80 into bucket

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Using chained hashing. You have a Hash table of size 7. You will add the following elements in the order given using the function %5. 18 - 44 - 31 - 11 - 8 А. 1 44 31 18 11 В. 3 4 6. 44 11 18 31 8 С. 1 3 4 6. 31 18 44 11 8. D. The correct answer is not listed 00 00 B.
Construct a Linear Hashing index for the following data entries: 1, 3, 5, 6, 7, 10, 14, 18, 21, 26, 27, 28, 30, 31, 32, 40, 46, 62, 63, 66, assuming there are four initial primary bucket pages and each bucket can hold up to four data entries. Show the snapshot of the index whenever an overflow page is created causing a bucket split.
The following hash table uses linear probing for collision resolution and the hash code value calculation simply returns the full integer value of the key. Based on the data in this table, list two possible different valid orders that the data could have been inserted into it. List the inserted value order with a space between each value and no commas. 0 42 1 14 2 21 3 4 5 19 6 Blank # 1 A Blank # 2 A/
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valsTable: o Empty-since-start 1 Empty-after-removal Occupied Hash table valsTable uses double probing with the hash functions hash1(key): key % 11 hash2(key): 5 - key % 5 and a table size of 11. 15 5 27 6. 7 HashInsert(valsTable, item 70) inserts item 70 into bucket Ex: 10 8 9 Hashlnsert(valsTable, item 62) inserts item 62 into bucket 10 Hashlnsert(valsTable, item 59) inserts item 59 into bucket 2. 3.
Calculate the final hash values for following keys, k={5,25,45}, given the hash function below: hi(k)=(hash1(k)+(i×hash2(k))) mod 20 hash1(k)=(k+2) mod 20 hash2(k)=17-(k mod 17)
vals Table: o 1 2 3 4 5 6 7 8 9 10 30 21 Empty-since-start Empty-after-removal Occupied Hash table valsTable uses double probing with the hash functions hash1(key): key % 11 hash2(key): 5-key % 5 and a table size of 11. HashInsert(vals Table, item 63) inserts item 63 into bucket Ex: 10 HashInsert(vals Table, item 62) inserts item 62 into bucket HashInsert(vals Table, item 32) inserts item 32 into bucket
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