Jump to level 1 Simplify (s^(mv-s)) to ¬sv-m 1. Select a law from the right to apply -(SA(mv-s)) Distributive (a^b)v(a^c)= a^(bvc) (avb)^(avc)= av(b^c) Commutative avb аль De Morgan's (a/b) (avb) Conditional a-b Laws a+b bva бла -av-b ¬а^-b -аvb (a+b)^(b-a) Complement av-a T а ча - F -T -F Identity алт - F - T - а avF Double negation 7-8 - а -a
Jump to level 1 Simplify (s^(mv-s)) to ¬sv-m 1. Select a law from the right to apply -(SA(mv-s)) Distributive (a^b)v(a^c)= a^(bvc) (avb)^(avc)= av(b^c) Commutative avb аль De Morgan's (a/b) (avb) Conditional a-b Laws a+b bva бла -av-b ¬а^-b -аvb (a+b)^(b-a) Complement av-a T а ча - F -T -F Identity алт - F - T - а avF Double negation 7-8 - а -a
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
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Simplify -(s^(mv-s)) to ¬sv-m
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Jump to level 1
1. Select a law from the right to apply
-(SA(MV-s))
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Distributive
(a^b)v(a^c)
(avb)^(avc) =
Commutative
avb
aлb
De Morgan's
-(a^b)
(avb)
U
Conditional
a→b
a+b
J
*
8
=
+
(
Laws
a^(bvc)
av(b^c)
¬аvb
9
K
bva
ba
-av-b
-а^-b
(a+b)^(b→a)
0
Complement
av ¬a
L
а па
-T
-F
Identity
алт
а
- T
= F
- F
avF - а
Double negation
=a
= T
-a
P
W
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