Jump to level 1 Simplify -(-q-(-m^-q)) to ¬q^m 1. Select a law from the right to apply -(-q-(-^-q)) Distributive (a^b)v(a^c) (avb)^(avc) Commutative avb аль De Morgan's (a^b) (avb) Conditional a-b a+b E E W Laws a^(bvc) av(b^c) bva bлa -av-b ¬ал-b ¬аvb M (a+b)^(b-a) Complement av-a = T а па E -T -F Identity aлT = F а = T - а avF Double negation =a =a
Jump to level 1 Simplify -(-q-(-m^-q)) to ¬q^m 1. Select a law from the right to apply -(-q-(-^-q)) Distributive (a^b)v(a^c) (avb)^(avc) Commutative avb аль De Morgan's (a^b) (avb) Conditional a-b a+b E E W Laws a^(bvc) av(b^c) bva bлa -av-b ¬ал-b ¬аvb M (a+b)^(b-a) Complement av-a = T а па E -T -F Identity aлT = F а = T - а avF Double negation =a =a
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Jump to level 1
Simplify -(-q-(-m^-q)) to ¬q^m
1. Select a law from the right to apply
-(-q-(-m -q))
Distributive
(a/b)v(a^c)
(avb)^(avc) =
Commutative
avb
axb
De Morgan's
Conditional
a-b
-(a^b) =
(avb) E
a b
=
-
=
=
Laws
a^(bvc)
av(b^c)
bva
ba
-av-b
-а^-b
¬avb
(a-b)^(b-a)
Complement
av ¬a
а па = F
-T
= T
-F
Identity
a^T
= F
= T
- а
avF
Double negation
л¬а =a
=a
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