Jse the normal distribution to find a confidence interval for a difference in proportions p – p2 given the relevant sample results. Assume the results come from random samples. A 99% confidence interval for p1 - P2 given counts of 274 yes out of 570 sampled for Group 1 and 339 yes out 325 sampled for Group 2 Give the best estimate for p – p2, the margin of error, and the confidence interval. Round your answers to three decimal places.

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# Educational Content: Constructing a Confidence Interval for Difference in Proportions

**Current Attempt in Progress**

Use the normal distribution to find a confidence interval for a difference in proportions \( p_1 - p_2 \) given the relevant sample results. Assume the results come from random samples.

A 99% confidence interval for \( p_1 - p_2 \) given counts of 274 "yes" out of 570 sampled for Group 1 and 339 "yes" out of 825 sampled for Group 2.

- **Objective**: Provide the best estimate for \( p_1 - p_2 \), the margin of error, and the confidence interval.

### Instructions

- **Round your answers to three decimal places.**

1. **Best estimate**:
   - Enter your calculated best estimate for the difference in proportions \( p_1 - p_2 \).

2. **Margin of error**:
   - Calculate and enter the margin of error for the confidence interval.

3. **Confidence interval**:
   - Enter the lower limit to the upper limit of the confidence interval.

**Interactive Elements**
- Input fields are provided for entering:
  - Best estimate
  - Margin of error
  - Lower and upper limits of the confidence interval
  
### Functionality

- **Save for Later**: Allows you to save your current work and return to it at another time.
  
- **Attempts**: You have a total of 4 attempts available for submitting your answer. 

- **Submit Answer**: Click this to submit your developed solution for evaluation.
Transcribed Image Text:# Educational Content: Constructing a Confidence Interval for Difference in Proportions **Current Attempt in Progress** Use the normal distribution to find a confidence interval for a difference in proportions \( p_1 - p_2 \) given the relevant sample results. Assume the results come from random samples. A 99% confidence interval for \( p_1 - p_2 \) given counts of 274 "yes" out of 570 sampled for Group 1 and 339 "yes" out of 825 sampled for Group 2. - **Objective**: Provide the best estimate for \( p_1 - p_2 \), the margin of error, and the confidence interval. ### Instructions - **Round your answers to three decimal places.** 1. **Best estimate**: - Enter your calculated best estimate for the difference in proportions \( p_1 - p_2 \). 2. **Margin of error**: - Calculate and enter the margin of error for the confidence interval. 3. **Confidence interval**: - Enter the lower limit to the upper limit of the confidence interval. **Interactive Elements** - Input fields are provided for entering: - Best estimate - Margin of error - Lower and upper limits of the confidence interval ### Functionality - **Save for Later**: Allows you to save your current work and return to it at another time. - **Attempts**: You have a total of 4 attempts available for submitting your answer. - **Submit Answer**: Click this to submit your developed solution for evaluation.
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