Jse the equation R= where L = 1609 m, A = PI•R2 (in meters?), and p = 1.7 x 108 ohm•meter. First find the cross-sectional area: %3D

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hi, can you help me to understand this problem by helping me through STEP BY STEP solution. The answer is given in the photo that i provide and here is the problem

Determine the resistance of a 1-mile length of 12-gauge copper wire. Given: 1 mile = 1609 meters and diameter = 0.2117 cm.


Check Your Understanding Answer
Answer: 7.8 ohms
Use the equation
R = P
A
where L = 1609 m, A = PI•R2 (in meters?), and p = 1.7 x 108 ohm•meter. First find the cross-sectional area:
A = PI•R? = (PI) •[ (0.002117 m) / 2)]² = 3.519 x 106 m²
Now substitute into the above equation to determine the resistance.
R = (1.7 x 10 8 ohm •m) •
R=7.8 (7.7709 ohm)
(1609 m) / (3.519 x 10-6 m²)
Transcribed Image Text:Check Your Understanding Answer Answer: 7.8 ohms Use the equation R = P A where L = 1609 m, A = PI•R2 (in meters?), and p = 1.7 x 108 ohm•meter. First find the cross-sectional area: A = PI•R? = (PI) •[ (0.002117 m) / 2)]² = 3.519 x 106 m² Now substitute into the above equation to determine the resistance. R = (1.7 x 10 8 ohm •m) • R=7.8 (7.7709 ohm) (1609 m) / (3.519 x 10-6 m²)
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