John walks 2.00 km north, then turns right and walks 2.00 km east. His speed is 2.00 m/s during the entire stroll. Part A What is the magnitude of his displacement, from beginning to end? Express your answer in kilometers. ? d = km
John walks 2.00 km north, then turns right and walks 2.00 km east. His speed is 2.00 m/s during the entire stroll. Part A What is the magnitude of his displacement, from beginning to end? Express your answer in kilometers. ? d = km
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem 1.75**
John walks 2.00 km north, then turns right and walks 2.00 km east. His speed is 2.00 m/s during the entire stroll.
**Part A**
What is the magnitude of his displacement, from beginning to end? Express your answer in kilometers.
\[ d = \, \_\_\_ \text{ km} \]
Incorrect; Try Again; 3 attempts remaining
---
**Explanation:**
John's motion can be visualized as a right-angled triangle where:
- The first leg is 2.00 km north.
- The second leg is 2.00 km east.
The displacement is the hypotenuse of this triangle, calculated using the Pythagorean theorem:
\[ \text{Displacement} = \sqrt{(2.00^2 + 2.00^2)} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe93cb2ca-1df2-4e1a-b3ee-5d48a1415c33%2F13fd3c3d-58bc-47d1-8295-9ad55a841169%2Fq9dx1a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 1.75**
John walks 2.00 km north, then turns right and walks 2.00 km east. His speed is 2.00 m/s during the entire stroll.
**Part A**
What is the magnitude of his displacement, from beginning to end? Express your answer in kilometers.
\[ d = \, \_\_\_ \text{ km} \]
Incorrect; Try Again; 3 attempts remaining
---
**Explanation:**
John's motion can be visualized as a right-angled triangle where:
- The first leg is 2.00 km north.
- The second leg is 2.00 km east.
The displacement is the hypotenuse of this triangle, calculated using the Pythagorean theorem:
\[ \text{Displacement} = \sqrt{(2.00^2 + 2.00^2)} \]
![**Problem Description:**
**Part B**
If Jane starts at the same time and place as John but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to arrive at the endpoint just when John does?
**Instructions:**
Express your answer in meters per second.
**Answer Input:**
\[
v = \_\_\_\_ \ \text{m/s}
\]
**Submission Options:**
- [Submit]
- [Request Answer]
**Feedback Section:**
- [Provide Feedback]
This problem involves determining the necessary speed for Jane to reach the destination simultaneously with John, given her straight path.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe93cb2ca-1df2-4e1a-b3ee-5d48a1415c33%2F13fd3c3d-58bc-47d1-8295-9ad55a841169%2Ft0o7qc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Description:**
**Part B**
If Jane starts at the same time and place as John but walks in a straight line to the endpoint of John's stroll, at what speed should she walk if she wants to arrive at the endpoint just when John does?
**Instructions:**
Express your answer in meters per second.
**Answer Input:**
\[
v = \_\_\_\_ \ \text{m/s}
\]
**Submission Options:**
- [Submit]
- [Request Answer]
**Feedback Section:**
- [Provide Feedback]
This problem involves determining the necessary speed for Jane to reach the destination simultaneously with John, given her straight path.
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