Jeff has been offered a job to fill a barn with hay. How much hay (volume) can go in the barn? The picture shows the dimensions of the barn. 6 ft 27ft 43ft The volume of the barn is 73ft = Does not need paint ft 3

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement:**

Jeff has been offered a job to fill a barn with hay. How much hay (volume) can go in the barn?

The picture shows the dimensions of the barn.

**Diagram Description:**

The barn is depicted as a rectangular prism with a triangular prism on top. Here are the dimensions provided in the illustration:

- The height of the rectangular prism (without the roof) is **27 ft**.
- The length of the barn is **73 ft**.
- The width of the barn is **43 ft**.
- The height of the triangular prism (representing the roof) is **6 ft**.

A key indicates that the shaded area does not need paint.

**Math Calculation:**

Calculate the volume of the barn:
- **Rectangular section**: \( \text{Length} \times \text{Width} \times \text{Height} \)
- **Triangular section (roof)**: \( \frac{1}{2} \times \text{Base} \times \text{Height} \times \text{Length} \)

**Answer Format:**

The volume of the barn is \( \_\_\_\_\_ \, \text{ft}^3 \).
Transcribed Image Text:**Problem Statement:** Jeff has been offered a job to fill a barn with hay. How much hay (volume) can go in the barn? The picture shows the dimensions of the barn. **Diagram Description:** The barn is depicted as a rectangular prism with a triangular prism on top. Here are the dimensions provided in the illustration: - The height of the rectangular prism (without the roof) is **27 ft**. - The length of the barn is **73 ft**. - The width of the barn is **43 ft**. - The height of the triangular prism (representing the roof) is **6 ft**. A key indicates that the shaded area does not need paint. **Math Calculation:** Calculate the volume of the barn: - **Rectangular section**: \( \text{Length} \times \text{Width} \times \text{Height} \) - **Triangular section (roof)**: \( \frac{1}{2} \times \text{Base} \times \text{Height} \times \text{Length} \) **Answer Format:** The volume of the barn is \( \_\_\_\_\_ \, \text{ft}^3 \).
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