JC-22) Double Slit Experiment Light of 600.0 nm wavelength is used to perform a double slit experiment. The bright fringes are found to be 1.8 mm apart on the viewing screen. What will the fringe separation be gif the light is changed to a wavelength of 400.0 nm?

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Explain the steps to find the answer, which equation you are using and why you are using it. Also a small reflection about the problem.  Thanks.

JC-22) Double Slit Experiment
Light of 600.0 nm wavelength is used to perform a double slit experiment. The
bright fringes are found to be 1.8 mm apart on the viewing screen. What will the fringe
separation be gif the light is changed to a wavelength of 400.0 nm?
Transcribed Image Text:JC-22) Double Slit Experiment Light of 600.0 nm wavelength is used to perform a double slit experiment. The bright fringes are found to be 1.8 mm apart on the viewing screen. What will the fringe separation be gif the light is changed to a wavelength of 400.0 nm?
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Step 1

wavelength of light = 600 nm distance between bright fringes (β)= 1.8 mm Let the distance between the slits and the screen = DLet the separation between the slits = d 

 

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