Answered: Java Input class main {…

Java Input class main { public static void main(String args[]) { byte x = 64; int i; byte y; i = x << 2; y = (byte) (x << 2) System.out.print(i + " " + y); } } Find output

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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1、Counting Primitive Operations void STRAITMAXMIN(A,n,max,min) //Set the maximum value in A to max and the minimum value to min { int i,n max=min=A[1] for i=2 to n { if A[i]> max max=A[i]; if A[i]< min min=A[i]; } }
1- public class MathF{ public static void main(String[] args) { char[] grade=new char[4]; 4 grade[1]='B'; grade[3]='C'; Integer d1= new Integer(6); 7 Integer d2= new Integer(10); 8- if(d1!= d2){ System.out.println("grades do not match "); 10 System.out.println("Result: "+Math.sqrt(d1+d2)); 11 } 5 12 else 13- { System.out.println("Marks are same"); 14 for (int i=0;i<4;i++) System.out.println(grade[i]); } 16 }} Answer:
Case Diagram and UML Class Diagram for this java code : (Below the code give some constructive critiques about the UML class diagram)…. Thanks import java.util.*; public class BeverlyBreads{public static void main(String[] args){Scanner input = new Scanner(System.in); //Array for breads String[] breads = new String[5]; //Bread choices breads[0] = "White Bread"; breads[1] = "Wheat Bread"; breads[2] = "Rye Bread"; breads[3] = "Pumpernickel Bread"; breads[4] = "Baguette"; //Prices for the breads double[] prices = new double[5]; prices[0] = 2.99; prices[1] = 3.49; prices[2] = 3.99; prices[3] = 4.49; prices[4] = 4.99; //Customer's Name System.out.println("Enter customer's name: "); String name = input.nextLine(); //Customer's Phone Number System.out.println("Enter customer's phone number: "); String phoneNumber = input.nextLine(); //Bread Selection System.out.println("Which bread would you like to order?"); for(int i = 0; i < breads.length; i++) { System.out.println(breads[i] + "…
// Return remainder after integer division // Global variables int a = 4; int b = 30; int main() { // Use registers for local variables int remainder; int divisor; } if (a > b) { } else { } remainder = a; divisor = b; } remainder = b; divisor = a; while (remainder > divisor) { remainder -= divisor; return remainder;
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#include using namespace std; class fraction{ float d,s; public: fraction() { d=0; s=1; fraction(int a, int b) { d=%3; s=b3; } void print() { cout<
UML Design for Turing Machine Description: An electro-mechanical device used by the British cryptologists to help decipher German Enigma-machine-encrypted secret messages during World War II. A Turing Machine is a very simple abstract model of computation. The machine has an infinite tape that is divided into cells (or squares). Each cell contains a symbol (or character) chosen from some small set of possible symbols. Most of the cells are blank, that is, they contain the blank symbol. The number of non-blank cells is finite. The machine is located on one of the cells, and it can only "see" the symbol in the cell where it is located. It can write a new value to that cell. It can move left or right on the tape, one cell at a time. The machine is in one of a fixed, finite number of possible states. One of the states is the halt state. A Turing Machine has a table of rules. The table of rules is the program for the machine. A rule tells the machine what action to take when it is in a…
Exponent y Catherine Arellano mplement a recursive function that returns he exponent given the base and the result. for example, if the base is 2 and the result is 3, then the output should be 3 because the exponent needed for 2 to become 8 is 3 (i.e. 23 = 8) nstructions: 1. In the code editor, you are provided with a main() function that asks the user for two integer inputs: 1. The first integer is the base 2. The second integer is the result 2. Furthermore, you are provided with the getExponent() function. The details of this function are the following: 1. Return type - int 2. Name - getExponent 3. Parameters 1. int - base 2. int - result 4. Description - this recursive function returns the exponent 5. Your task is to add the base case and the general case so it will work Score: 0/5 Overview 1080 main.c exponent.h 1 #include 2 #include "exponent.h" 3 int main(void) { 4 int base, result; 5 6 printf("Enter the base: "); scanf("%d", &base); 7 8 9 printf("Enter the result: ");…
PROBLEM STATEMENT: An anagram is a word that has been rearranged from another word, check tosee if the second word is a rearrangement of the first word. public class AnagramComputation{public static boolean solution(String word1, String word2){// ↓↓↓↓ your code goes here ↓↓↓↓return true;}} Can you help me with this java question the language is java please use the code I gave
change to ada language import java.util.scanner; public class problem41 { public static void main(string[] args) { scanner input = new scanner(system.in); int positives = 0; // count the number of positive numbers int negatives = 0; // count the number of negative numbers int count = 0; // count all numbers double total = 0; // accumulate a totol // promopt the user to enter an integer or 0 to exit system.out.print("enter an integer, the input ends if it is 0: "); int number = input.nextint(); if (number == 0) { // test for sentinel value system.out.println("no numbers are entered except 0"); system.exit(1); } while (number != 0) {// test for sentinel value if (number > 0) { positives++; // increase positives } else { negatives++; // increase negatives } total += number; // accumulate total count++; // increase the count number = input.nextint();//read the next number } // calculate the average double average = total / count; // display results system.out.println( "the number of…
public static void main(String [] args) { // Step 2: Construct a Day object representing today // and assign it to a variable called aDay // Step 3: Construct a Day object representing the day for our Exam1 on March 1, 2022, and assign it to a variable called examOne // // // Step 4: Declare three integer variables called year, month and day with initial values of 2022, 4, 12. // // 4 // Step 5: Construct a Day object using the three variables and assign it to a variable called examTwo 6. :7 28 29 // // Step 6: Display the three days on separate lines without any messages 30 31 // 32 33 // Step 7: Display the number of days as a positive integer between the two exams with a message 34 35 // 36 // "Number of days between the two exams: " 37 38 39 // Step 8: Update aDay to the day two days later 40 41 // Step 9: Print the year, month and day of aDay, one value per line without any messages 42 43 // 44 45 } 46 47