Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 34 students, she finds 3 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 34 students, she finds 3 who eat cauliflower. Obtain and interpret
a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
A Click the icon to view Agresti and Coull's method.
Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.
(Round to three decimal places as needed.)
O A. The proportion of students who eat cauliflower on Jane's campus is between
and
90% of the time.
O B. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between
and
O C. There is a 90% chance that the proportion of students who eat cauliflower in Jane's sample is between
and
O D. One is 90% confident that the proportion of students who eat cauliflower on Jane's campus is between
and
Transcribed Image Text:Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 34 students, she finds 3 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. A Click the icon to view Agresti and Coull's method. Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) O A. The proportion of students who eat cauliflower on Jane's campus is between and 90% of the time. O B. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between and O C. There is a 90% chance that the proportion of students who eat cauliflower in Jane's sample is between and O D. One is 90% confident that the proportion of students who eat cauliflower on Jane's campus is between and
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