Jamie needs to take her dog to the groomer. The groomer charges $45 if the dog is 12 pounds or less. They charge $55 if the dog is over 12 and no more than 45 pounds. If the dog is over 45 pounds, the charge is $55 plus 3 times the number of pounds over 45 that the dog is. Which function represents the grooming fee, f(x), in terms of weight, x, and how much will Jamie pay if her dog weighs 46 pounds? x< 12 12 < x < 45; She will pay $193. 45, O f(x) = { 55, 55 +3(x), X> 45 0 < x < 12 12 45 45, 0 45 45, OSxs12 O f(x) = 55 – 3(x – 45), 55, 12 sxS 45; She will pay $52. X 2 45

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Jamie needs to take her dog to the groomer. The groomer charges $45 if the dog is 12 pounds or less. They charge $55 if the dog is over 12 and no more than 45 pounds. If the dog is over
45 pounds, the charge is $55 plus 3 times the number of pounds over 45 that the dog is. Which function represents the grooming fee, f(x), in terms of weight, x, and how much will Jamie pay
if her dog weighs 46 pounds?
45,
X < 12
O f(x) =
55,
12 <x< 45; She will pay $193.
55 +3(x),
X> 45
45,
0 <x<12
O f(x) =
55,
12 <x < 45; She will pay $103.
3(x – 45),
X> 45
45,
0 < x< 12
O f(x)
55,
12 < x< 45; She will pay $58.
55 +3(x – 45),
X> 45
-
45,
0<x<12
12 <xS 45; She will pay $52.
X2 45
O f(x)
55,
55- 3(х — 45),
Transcribed Image Text:Jamie needs to take her dog to the groomer. The groomer charges $45 if the dog is 12 pounds or less. They charge $55 if the dog is over 12 and no more than 45 pounds. If the dog is over 45 pounds, the charge is $55 plus 3 times the number of pounds over 45 that the dog is. Which function represents the grooming fee, f(x), in terms of weight, x, and how much will Jamie pay if her dog weighs 46 pounds? 45, X < 12 O f(x) = 55, 12 <x< 45; She will pay $193. 55 +3(x), X> 45 45, 0 <x<12 O f(x) = 55, 12 <x < 45; She will pay $103. 3(x – 45), X> 45 45, 0 < x< 12 O f(x) 55, 12 < x< 45; She will pay $58. 55 +3(x – 45), X> 45 - 45, 0<x<12 12 <xS 45; She will pay $52. X2 45 O f(x) 55, 55- 3(х — 45),
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